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gtnhenbr [62]
3 years ago
13

A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g).

the ratio of the rms speed of the argon molecules to that of the hydrogen is
Physics
1 answer:
qaws [65]3 years ago
7 0

To solve this problem, let us recall that the formula for gases assuming ideal behaviour is given as:

rms = sqrt (3 R T / M)

where

R = gas constant = 8.314 Pa m^3 / mol K

T = temperature

M = molar mass

Now we get the ratios of rms of Argon (1) to hydrogen (2):

rms1 / rms2 = sqrt (3 R T1 / M1) / sqrt (3 R T2 / M2)

or

rms1 / rms2 = sqrt ((T1 / M1) / (T2 / M2))

rms1 / rms2 = sqrt (T1 M2 / T2 M1)

Since T1 = 4 T2

rms1 / rms2 = sqrt (4 T2 M2 / T2 M1)

rms1 / rms2 = sqrt (4 M2 / M1)

and M2 = 2 while M1 = 40

rms1 / rms2 = sqrt (4 * 2 / 40)

rms1 / rms2 = 0.447

 

Therefore the ratio of rms is:

<span>rms_Argon / rms_Hydrogen = 0.45</span>

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Jonah is trying to move his 22-kg desk by pushing on it with a force of 130 N, but his brother is leaning on it with a downward
Dafna11 [192]

Answer:

0.54

Explanation:

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Weight force mg pulling down

Applied force 24 N pushing down

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Friction force Fnμ pushing left

Sum of the forces in the y direction:

∑F = ma

Fn − mg − 24 = 0

Fn = mg + 24

Fn = (22)(9.8) + 24

Fn = 240

Sum of the forces in the x direction:

∑F = ma

130 − Fnμ = 0

Fnμ = 130

μ = 130 / Fn

μ = 130 / 240

μ = 0.54

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Explanation:

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A material used for electrical wiring must have
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A certain amount of Conductivity
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1. When does raising the temperature of a gas increase its pressure? when volume is increased and the number of particles is con
Neporo4naja [7]

Answer:

when volume and the number of particles are constant

Explanation:

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

\frac{P1}{T1} = \frac{P_{2}}{T_{2}}

The ideal gas law is the equation PV = nRT

Where;

P is the pressure.

V is the volume.

n is the number of moles of substance.

R is the ideal gas constant.

T is the temperature.

Generally, raising the temperature of an ideal gas would increase its pressure when volume and the number of particles are constant.

This ultimately implies that, when volume and the number of particles are held constant, there would be a linear relationship between the temperature and pressure of a gas i.e temperature would be directly proportional to the pressure of the gas. Thus, an increase in the temperature of the gas would cause an increase in the pressure of the gas at constant volume and number of particles.

3 0
3 years ago
Pls answer these ASAP....THANK YOU...
natali 33 [55]

Density = (mass) / (volume) <== MEMORIZE THIS !

1).  Mass = 50 g.  Volume = 100 cm³.  Density = (mass) / (volume)

===================================

2).  Volume = (length) ·(width) ·(height) = (4cm) ·(4cm) ·(4cm) = 64 cm³

Mass = 672 g.  Density = (mass) / (volume)

===================================

3).  Volume = (length) ·(width) ·(height)

Length = 1 meter = 100 cm

Width = 10 cm = 10 cm

Height = 22 mm = 2.2 cm

Volume = (100 cm) (10 cm) (2.2 cm) = 2,200 cm³

Mass = 42,460 g

Density = (mass) / (volume)

3 0
2 years ago
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