What is the conversion factor between km/h2 and m/s2?

Radar use reflected microwaves to detect objects and measure their... what?

Sloan [31]

Height and depth..... for sure....

7 0

3 years ago

Joe Burrow of the Cincinnati Bengals ate a turkey sandwich and an apple for lunch. Later that day, he spent 2 hours on the footb

Nostrana [21]

Answer:

A Thermal energy was converted to kinetic energy

7 0

2 years ago

Someone please help its a simple power problem.

SOVA2 [1]

Well 200 doubled or (x2)=400 if that’s what it means

7 0

2 years ago

Twin brothers, Andy and Brian, can mow their grandparents lawn together in 1212 minutes. Brian would mow the lawn by himself

Karo-lina-s [1.5K]

Answer:

It will take Andy 1.198minutes to mow the lawn and it will take Brian 1,209.98minutes to mow the same lawn.

Step-by-step explanation:

Using the simultaneous equation concept, let A denote Andy and B be Brian

Andy and Brian can mow the lawn for 1212minutes i.e A+B = 1212..eqn 1

If Brian would mow the lawn by himself in 1010 minutes more than it would take Andy, this means B=1010A...eqn 2.

Substituting eqn 2 into eqn 1

Equation 1 becomes

A+1010A=1212

1011A=1212

A=1212/1011

A=1.198

B = 1010×1.198

B=1,209.98

Therefore, It will take Andy 1.198minutes to mow the lawn and it will take Brian 1,209.98minutes to mow the same lawn.

6 0

3 years ago

A wire of Nichrome (a nickelâ€“ chromiumâ€“ iron alloy commonly used in heating elements) is 1.0 m long and 1.0 mmÂ² in cross-se

Lyrx [107]

Answer:

The conductivity of Nichrome is $2\times 10^6\ S/m$ .

Explanation:

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:

$R=\frac{V}{A}=\frac{2.0}{4.0}=0.5\ \Omega$

Now, resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:

$R=\rho\frac{L}{A}$

Where, $\rho\to resistivity\ of\ Nichrome$

Now, plug in all the values given and solve for $\rho$ . This gives,

$0.5\ \Omega=\rho\frac{1.0\ m}{1\times 10^{-6}\ m^2}\\\\\rho=\frac{0.5\times 1\times 10^{-6}}{1.0}=0.5\times 10^{-6}\ \Omega-m$

Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

$\sigma=\frac{1}{\rho}=\frac{1}{0.5\times 10^{-6}}=2\times 10^6\ S/m$

Conductivity is measured in Siemens per meter (S/m)

Therefore, the conductivity of Nichrome is $2\times 10^6\ S/m$ .

7 0

3 years ago