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3 years ago

6

an aeroplane taking off from a field has a run of 500m. What is the acceleration and take off velocity if it leaves the ground 1

0 s after the start

1 answer:

zaharov [31]3 years ago

6 0

Answer: 50m/s

Explanation: S = D/T which means <em>speed</em> equals <em>distance </em>divided by <em>time</em>.

so 500m divided by 10 : 50m/s

Hope this helps for many people.

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How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?

slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

<em>applied force, F = 600 N</em>
<em>mass of the truck, m = 1,500 kg</em>
<em>speed of the truck, v = 2 m/s</em>

The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>

F = ma

$F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s$

Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.

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