Range of a projectile motion is given by
R = v cos θ / g (v sin θ + sqrt(v^2 sin^2 θ + 2gy_0)); where R = 188m, θ = 41°, g = 9.8m/s^2, y_0 = 0.9
188 = v cos 41° / 9.8 (v sin 41° + sqrt(v^2 sin^2 41° + 2 x 9.8 x 0.9)) = 0.07701(0.6561v + sqrt(0.4304 v^2 + 17.64)) = 0.05053v + 0.07701sqrt(0.4304v^2 + 17.64)
0.07701sqrt(0.4304v^2 + 17.64) = 188 - 0.05053v
0.005931(0.4304v^2 + 17.64) = 35344 - 19v + 0.002553v^2
0.002553v^2 + 0.1046 = 35344 - 19v + 0.002553v^2
19v = 35344 - 0.1046 = 35343.8954
v = 35343.8954/19 = 1860 m/s
Answer:
1028 slits/mm
Explanation:
We are given that
Wavelength of light, 
1nm=
n=1
We have to find the number of slits per mm are marked on the grating.
We know that
Using the formula
1m=
mm
Number of slits=
Number of slits=
/mm
Number of slits=1028/mm
Hence, 1028 slits/mm are marked on the grating.
If you can get a clearer image, I would be able to complete most, if not, all problems on the paper.
Use the equation F=ma to solve for the acceleration
Force: 50 N
Mass: 100kg
50=100a
a= .5 m/s/s
