The key to solving this problem is density. Density determines the mass of a molecule for a certain volume. Kia is given a beaker containing 100 g which volume is at <span>100 mL mark. Then the density of the liquid would be:
</span>density=mass/volume
density= 100g/ 100ml= 1g/ml
If t<span>he water now comes up to the 50 mL mark, then the weight would be:
</span>density = mass/volume
mass = volume * density
<span>mass = 50ml * (1g/ml)= 50g</span>
The balanced chemical reaction is written as:
<span>Zn + 2AgNO3 = Zn(NO3)2 + 2Ag
To determine the grams of silver metal that is being produced, it is important to first determine which is the limiting reactant and the excess reactant from the given initial amounts. We do as follows:
4.35 g Zn ( 1 mol / 65.38 g ) ( 2 mol AgNO3 / 1 mol Zn ) = 0.1331 mol AgNO3 needed
35.8 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Zn / 2 mol AgNO3 ) = 0.1054 mol Zn needed
Therefore, the limiting reactant would be the zinc metal since it would be consumed completely in the reaction. The excess amount of AgNO3 would be:
0.2107 mol AgNO3 - 0.1331 mol AgNO3 = 0.0776 mol AgNO3 left ( 169.87 g / 1 mol ) = 13.19 g AgNO3 left
0.0665 mol Zn ( 2 mol Ag / 1 mol Zn) ( 107.9 g / 1 mol) = 14.3581 g Ag produced</span>
Answer:
27.22 dm³
Explanation:
Given parameters:
number of moles = 1 mole
temperature= 50°C, in K gives 50+ 273 = 323K
Pressure= 98.6kpa in ATM, gives 0.973 ATM
Solution:
Since the unknown is the volume of gas, applying the ideal gas law will be appropriate in solving this problem.
The ideal gas law is mathematically expressed as,
Pv=nRT
where P is the pressure of the gas
V is the volume
n is the number of moles
R is the gas constant
T is the temperature
Input the parameters and solve for V,
0.973 x V = 1 x 0.082 x 323
V= 27.22 dm³
I believe that would be a decomposer
The 2nd one is the right answer
Hope this helped
