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Alenkinab [10]
3 years ago
9

If I need 2.2 moles of CO2 , and I have excess Fe2O3 , how many moles of C do I need?

Chemistry
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

0.733 mol.

Explanation:

  • From the balanced equation:

<em>2Fe₂O₃ + C → Fe + 3CO₂,</em>

It is clear that 1.0 moles of Fe₂O₃  react with 1.0 mole of C to produce 1.0 mole of Fe and 3.0 moles of CO₂.

  • Since Fe₂O₃ is in excess, C will be the limiting reactant.

<u><em>Using cross multiplication:</em></u>

1.0 mole of C produces → 3.0 moles of CO₂, from the stichiometry.

??? mole of C produces → 2.2 moles of CO₂.

∴ The no. of moles of C needed to produce 2.2 moles of CO₂ = (1.0 mole of C) (2.2 mole of CO₂) / (3.0 mole of CO₂) = 0.733 mol.

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What is the mass of a titanium alloy that has a heat of fusion of 422.5 joules/gram and requires 2,960 joules of energy to melt
Marianna [84]

 The mass  of titanium alloy    is 7.01 g


 <u><em>calculation</em></u>

Q=mHF

where

Q(heat)= 2960 j

M(mass) = ?

Hf( heat  of fusion) = 422.5 j/g

make M the subject of the formula  by  diving both side of equation by Hf

M=Q/Hf

M= 2960 j/422.5 j/g = 7.01 g

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Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig
BigorU [14]

Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

In first place, the balanced reaction is:

2 HgO  → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • HgO: 2 moles
  • Hg: 2 moles
  • O₂: 1 moles  

The molar mass of the compounds is:

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  • Hg: 200.59 g/mole
  • O₂: 32 g/mole  

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:  

  • HgO: 2 moles× 216.59 g/mole= 433.18 grams
  • Hg: 2 moles× 200.59 g/mole= 401.18 grams
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Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

moles of HgO=\frac{250 grams of O_{2} x2 moles of HgO}{32grams of O_{2}}

<u><em>moles of HgO= 15.625 moles≅ 15.63 moles</em></u>

Finally, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

Learn more about reaction stoichiometry:

  • <u>brainly.com/question/24741074 </u>
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When you accumulate many atoms, these metals can form a "sea of electrons"  because they all have loose electrons interacting with each other. This allows easy conduction of heat and electricity.

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