Answer:
5
Explanation:
Firstly, we convert what we have to percentage compositions.
There are two parts in the molecule, the sulphate part and the water part.
The percentage compositions is as follows:
Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%
The water part = 100 - 64 = 36%
Now, we divide the percentages by the molar masses.
For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol
For the H2O = 2(1) + 16 = 18g/mol
Now we divide the percentages by these masses
Sulphate = 64/160 = 0.4
Water = 36/18 = 2
The ratio is thus 0.4:2 = 1:5
Hence, there are 5 water molecules.
Answer:
domain bacteria
Explanation:
Salmonella and E. coli are same in the sense that they are both bacteria,
This answer should have four signifigant features
Explanation:
I had this on a test and got it right :D
The following Balanced Reaction will take place:
Zn + 2HCl → ZnCl₂ + H₂
In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction
<u>Amount of HCl required to completely react with 2 moles of Zn:</u>
Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn
<u>Identifying the Limiting Reagent:</u>
But we are only given 3 moles of HCl where we need 4 moles to completely react.
So, since HCl is in less amount, it is the Limiting Reagent
