Question

(a) The rate of the reaction in terms of the "disappearance of reactant" includes the change in the concentration of the

Answer 1

Answer:

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

Explanation:

Average rate of the reaction is defined as ratio of change in concentration of reactant with respect to given interval of time.

$R_{avg}=-\frac{[A]_2-[A]_1}{t_2-t_1}$

Where :

$A_1$ = initial concentration of reactant at $t_1$.

$A_2$ = Final concentration of reactant at $t_2$.

2A+3B → 3C+2D

$R_{avg}=-\frac{1}{2}\frac{[A]_2-[A]_1}{t_2-t_1}$

The concentration of A at ($t_1=0 seconds$ ) = $A_1=0.0400 M$

The concentration of A at ($t_2=20 seconds$ ) = $A_2=0.0240 M$

The average rate of reaction in terms of the disappearance of reactant A in an interval of 0 seconds to 20 seconds is :

$R_{avg}=-\frac{1}{2}\times \frac{0.0240 M-0.0400 M}{20-0}=0.0004 M/s$

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.