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Elden [556K]
3 years ago
10

(a) The rate of the reaction in terms of the "disappearance of reactant" includes the change in the concentration of the

Chemistry
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

Explanation:

Average rate of the reaction is defined as ratio of change in concentration of reactant with respect to given interval of time.

R_{avg}=-\frac{[A]_2-[A]_1}{t_2-t_1}

Where :

A_1 = initial concentration of reactant at t_1.

A_2 = Final concentration of reactant at t_2.

2A+3B → 3C+2D

R_{avg}=-\frac{1}{2}\frac{[A]_2-[A]_1}{t_2-t_1}

The concentration of A at (t_1=0 seconds ) = A_1=0.0400 M

The concentration of A at (t_2=20 seconds ) = A_2=0.0240 M

The average rate of reaction in terms of the disappearance of reactant A in an interval of 0 seconds to 20 seconds is :

R_{avg}=-\frac{1}{2}\times \frac{0.0240 M-0.0400 M}{20-0}=0.0004 M/s

The average rate of the reaction in terms of disappearance of A is 0.0004 M/s.

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A 5.00-g sample of copper metal at 25.0 °C is heated by the addition of 133 J of energy. The final temperature of the copper is
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<u>Answer:</u> The final temperature of the copper is 95°C.

<u>Explanation:</u>

To calculate the final temperature for the given amount of heat absorbed, we use the equation:

Q= m\times c\times \Delta T

Q = heat absorbed  = +133 J (heat is added to the system)

m = mass of copper = 5.00 g

c = specific heat capacity of copper = 0.38 J/g ° C      

\Delta T={\text{Change in temperature}}=T_2-T_1

T_1=25^oC

Putting values in above equation, we get:

+133J=5.00g\times 0.38J/g^oC\times (T_2-25)\\\\T_2=95^oC

Hence, the final temperature of the copper is 95°C.

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d. CF_4 is non-polar, since it's a tetrahedral molecule with no lone pairs on carbon atom, all four C-F dipole moments cancel out to yield a net 0 dipole moment.

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