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Lena [83]
2 years ago
13

You drop a rock down a well and hear a splash 3 s later. As Charlie Brown would say, the well is 3 seconds deep. How fast is the

rock moving when it hits the water?
Physics
1 answer:
vampirchik [111]2 years ago
5 0
Since it was dropped, it should be the speed of gravity which is 9.8 meters/second
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PLZZZ HELP 100 POINTS WILL MARK BRAINELST
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A boat displaces a volume V of water as it floats on a fresh-water lake. When the boat moves into the ocean, what volume of salt
Mamont248 [21]

Answer:

Option (b)

Explanation:

let the weight of boat is W.  In equilibrium condition, the weight of boat is equal to the buoyant force acting on the boat.

The buoyant force acting on the boat is equal to the weight of water displaced by the boat.

In case of fresh water:

Weight of the boat = weight of fresh water displaced by the boat

W = Volume of fresh water displaced x density of fresh water x g

W = V x 1 x g

W = V x g ....... (1)

In case of salt water:

Let the volume of salt water displaced is V'.

Weight of the boat = weight of salt water displaced by the boat

W = Volume of salt water displaced x density of salt water x g

W = V' x 1.02 x g    ..... (2)

Equate equation (1) and equation (2), we get

V x g = V' x 1.02 x g

V' = 0.98 V

Thus, option (b) is true.

7 0
4 years ago
In a maneuver, the jet comes in for a landing on solid ground with a speed of 115 m/s, and its acceleration can have a maximum m
V125BC [204]

Answer:

17.1130952381 s

No

Explanation:

t = Time taken

u = Initial velocity = 115 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -6.72 m/s² (negative as it is decelerating)

From the equations of motion

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-115}{-6.72}\\\Rightarrow t=17.1130952381\ s

The minimum time required to stop is 17.1130952381 s

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-115^2}{2\times -6.72}\\\Rightarrow s=984.00297619\ m

The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.

4 0
3 years ago
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