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2 years ago

13

Someone please answer this, ill give you brainliest and your getting 100 points.

1 answer:

dsp732 years ago

8 0

Answer:

Option B is correct

Explanation:

A is denoted to lithosphere followed by B -asthenosphere .

Which is covered by lava of E(Mantal section)

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(a) Determine the capacitance of a Teflon-filled parallel-plate capacitor having a plate area of 1.80 cm2 and a plate separation

icang [17]

Explanation:

(a) Given that,

Area of a parallel plate capacitor, $A=1.8\ cm^2=1.8\times 10^{-4}\ m^2$

The separation between the plates of a capacitor, $d=0.01\ mm = 10^{-5}\ m$

The dielectric constant of, k = 2.1

When a dielectric constant is inserted between parallel plate capacitor, the capacitance is given by :

$C=\dfrac{k\epsilon_o A}{d}$

Putting all the values we get :

$C=\dfrac{2.1\times 8.85\times 10^{-12}\times 1.8\times 10^{-4}}{0.01\times 10^{-3}}\\\\C=3.345\times 10^{-10}\ F\\\\C=334.5\ pF$

(b) We know that the Teflon has dielectric strength of 60 MV/m, $E=60\times 10^6\ V/m$

The voltage difference between the plates at this critical voltage is given by :

$V=Ed\\\\V=60\times 10^6\times 0.01\times 10^{-3} \\\\V=600\ V$

or

V = 0.6 kV

3 0

3 years ago

How heavy is an object that displaces 400N of water in a pool?

julia-pushkina [17]

All we can say is that the object's volume is about 41 liters. That's the same as the volume of water displaced.

We can't say anything about the object's weight. There is no direct connection between the weight of the object and the weight of the water it displaces.

7 0

3 years ago

A novice pilot sets a plane’s controls, thinking the plane will fly at 2.50 × 102 km/h to the north. if the wind blows at 75 km/

serg [7]

Velocity of plane is given as

$v_1 = 2.50 * 10^2 km/h$ towards north

$v_2 = 75 km/h$ towards south east

we can write the two velocity in vector form

$v_1 = 2.50 * 10^2 \hat j$

$v_2 = 75 cos45 \hat i - 75 sin45 \hat j$

now the net velocity will be given as

$v_{net} = v_1 + v_2$

$v_{net} = 250\hat j + 53.03 \hat i - 53.03 \hat j$

$v_{net} = 53.03\hat i + 196.97 \hat j$

so the resultant velocity will be given as

$v_{net} = \sqrt{53.03^2 + 196.97^2}$

$v_{net} = 203.98 m/s$

and the angle of velocity will be

$\theta = tan^{-1}\frac{v_y}{v_x}$

$\theta = tan^{-1}\frac{196.97}{53.03} = 74.9 degree$

3 0

4 years ago

Net force of 200 newtons is applied to a wagon for 3 seconds

AveGali [126]

Momentum of the wagon increases by (200 x 3)

= 600 newton-sec

= 600 kg-m/sec

6 0

4 years ago

An important difference between waves and classical particles is that A. waves cannot interfere. B. particles cannot interfere.

pishuonlain [190]

<span>C. waves can only interfere destructively. </span>

5 0

3 years ago