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Mumz [18]
3 years ago
15

Twenty years ago a small town in Texas had a population of 10,000. The population has increased 8% each year since then. What is

the current population of this town?
Mathematics
1 answer:
zhenek [66]3 years ago
4 0
33,200...maybe. Farrah, I'm not so good at math.
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stiv31 [10]
$165 x 48 = $7920 which is what he has to pay in total for 48 months
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3 years ago
Question is based on Fraction
Genrish500 [490]

9514 1404 393

Answer:

  12,00,000 rupees

Step-by-step explanation:

The fraction originally intended for each son was ...

  (1/3)(1 -2/5) = 1/3(3/5) = 1/5

The fraction each son actually received was ...

  (1 -1/6)(1/5) = (5/6)(1/5) = 1/6

The difference in these amounts as a fraction of the original distribution is ...

  1/5 - 1/6 = (6/30) -(5/30) = 1/30

Then the original distribution is 30 times this difference:

  30×40000 rupees = 12,00,000 rupees

_____

<em>Additional comment</em>

Originally-intended distribution (rupees):

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  • each son: 2,40,000

Actual distribution:

  • brother: 2,00,000
  • wife: 4,00,000
  • each son: 2,00,000

1,00,000 = 1 lakh

6 0
3 years ago
Factor this polynomial 8a^2+2a-6
Naddik [55]
2(4a^2 +a +3)
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Maksim231197 [3]

Answer:

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