1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alisha [4.7K]
3 years ago
14

A proposed space station includes living quarters in a circular ring 50.0 m in diameter. At what angular speed should the ring r

otate so the occupants feel that they have the same weight as they do on Earth?
Physics
1 answer:
mel-nik [20]3 years ago
5 0
Given that the space station is free of gravitational force, it is required that it spins an certain speed to acquire centripetal acceleration.

In this case, you want that the centripetal acceleration, Ac, equals g (gravitational acceleration on the earth), becasue this will cause a centripetal force equal to the weight on earth.

The formula for centripetal acceleration is Ac = [angular velocity]^2*R

where R = [1/2]50.0m = 25.0 m

Ac = 9.81 m/s^2

=> [angular velocity]^2 = Ac/R = 9.81m/s^2v/ 25.0m = 0.3924 (rad/s)^2

[angular velocity] = √(0.3924) rad/s = 0.63 rad/s

Answer: 0.63 rad/s

 

You might be interested in
Increasing the amount of current that flows through a wire ______ the strength of an electromagnet
Anestetic [448]

Electromagnet is in form of solenoid

and the magnetic field due to solenoid is given as

B = \mu_0 n i

here

i = current in the loop

so when we increase the current in electromagnet the magnetic field of the solenoid will increase

this will increase the strength of the electromagnet

so the answer would be

<em>INCREASE</em>

7 0
4 years ago
Read 2 more answers
HELP QUICK PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
KIM [24]

Answer:

the answer is c

Explanation:

6 0
4 years ago
Read 2 more answers
10. Someone takes 11 minutes to walk up a hill 120m high. His weight is 550N.
belka [17]

Answer:

okay with you if you want to

8 0
2 years ago
A 120 g, 8.0-cm-diameter gyroscope is spun at 1000 rpm and allowed to precess. What is the precession period?
dolphi86 [110]

To solve this problem we will derive the expression of the precession period from the moment of inertia of the given object. We will convert the units that are not in SI, and finally we will find the precession period with the variables found. Let's start defining the moment of inertia.

I = MR^2

Here,

M = Mass

R = Radius of the hoop

The precession frequency is given as

\Omega = \frac{Mgd}{I\omega}

Here,

M = Mass

g= Acceleration due to gravity

d = Distance of center of mass from pivot

I = Moment of inertia

\omega= Angular velocity

Replacing the value for moment of inertia

\Omega= \frac{MgR}{MR^2 \omega}

\Omega = \frac{g}{R\omega}

The value for our angular velocity is not in SI, then

\omega = 1000rpm (\frac{2\pi rad}{1 rev})(\frac{1min}{60s})

\omega = 104.7rad/s

Replacing our values we have that

\Omega = \frac{9.8m/s^2}{(8*10^{-2}m)(104.7rad)}

\Omega = 1.17rad/s

The precession frequency is

\Omega = \frac{2\pi rad}{T}

T = \frac{2\pi rad}{\Omega}

T = \frac{2\pi}{1.17}

T = 5.4 s

Therefore the precession period is 5.4s

7 0
3 years ago
El espectro visible en el aire está comprendido entre la longitud de onda 450 nm del color azul, Determina la velocidad de propa
TiliK225 [7]

Answer:

v = 2,99913 10⁸ m / s

Explanation:

The velocity of propagation of a wave is

         v = λ f

in the case of an electromagnetic wave in a vacuum the speed that speed of light

         v = c

When the wave reaches a material medium, it is transmitted through a resonant type process, whereby the molecules of the medium vibrate at the same frequency as the wave, as the speed of the wave decreases the only way that they remain the relationship is that the donut length changes in the material medium

         λ = λ₀ / n

where n is the index of refraction of the material medium.

Therefore the expression is

           v = \frac{\lambda_o}{n} f

Let's look for the frequency of blue light in a vacuum

           f =\frac{c }{\lambda_o}  

           f = \frac{3 \ 10^8}{450 \ 10^{-9}}

           f = 6.667 10¹⁴ Hz

the refractive index of air is tabulated

           n = 1,00029

let's calculate

           v = \frac{450 \ 10^{-9} }{1.00029}  \ 6.667 \ 10^{14}450 10-9 / 1,00029 6,667 1014

            v = 2,99913 10⁸ m / s

we can see that the decrease in speed is very small

8 0
3 years ago
Other questions:
  • The roots of plants are important to photosynthesis because they...
    5·1 answer
  • Please hurry!!!!!!!.......
    6·2 answers
  • 102) Consider massive gliders that slide friction- free along a horizontal air track Glider A has a mass of 1 kg, aspeed of 1 m/
    5·1 answer
  • Two adjoining plane mirrors are separated by an angle of 100°. Light is incident on the first mirror at an angle of 70°. The lig
    14·2 answers
  • A car moving at a velocity of 25m/s, so how much distance it will travel in 5 seconds?
    8·1 answer
  • A bicycle travels 15 km in 30 minutes. What it's is average speed in km per hour
    8·2 answers
  • What are continuous, emission, and absorption spectra? How are they produced?
    15·1 answer
  • Acceleration is the magnitude of average velocity true or false
    6·1 answer
  • You must always include a direction when recording an amount of energy. Is this true?
    13·2 answers
  • Create a hypothesis for this testable question: How does price affect the amount of chocolate people buy?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!