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UkoKoshka [18]
4 years ago
14

Which of the following graphs correctly represents the relationship between the pressure and the volume of an ideal gas that is

held at constant temperature?
Physics
2 answers:
Lerok [7]4 years ago
7 0

Answer:

B is the answer given the previous answer.

Explanation:

This will just make it easier for people that have the question

vazorg [7]4 years ago
3 0
Well, you haven't given us much of a choice of graphs to pick from, have you.

If a sample of an ideal gas is held at constant temperature, then
its pressure and volume are inversely proportional ... the harder
you squeeze it, the smaller the volume gets, and less squeeze
produces more volume.

Actually, the product of (pressure) x (volume) is always the
same number.

The graph of that relationship is all in the first quadrant.
It starts out very high right next to the y-axis, then drops down
toward the x-axis while curving to the right and becoming horizontal,
and ends up trying to get closer and closer to the x-axis but never
actually becoming zero. 

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The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weigh
Serjik [45]

Answer:

89.16pounds

Explanation:

The equation that defines this problem is as follows

W=k/X^2

where

W=Weight

K= proportionality constant

X=distance from the center of Earth

first we must find the constant of proportionality, with the first part of the problem

k=WX^2=131x3960^2=2054289600pounds x miles^2

then we use the equation to calculate the woman's weight with the new distance

W=2054289600/(4800)^2=89.16pounds

4 0
3 years ago
What is the symbol F g mean
leva [86]

Answer:

Disambiguation

Explanation:

Fg is an abbreviation used in physics to describe the amount of force exerted by gravity on an object, normally represented in units such as the newton.

4 0
3 years ago
Read 2 more answers
I need help plz!!! Please help...
RSB [31]

Answer: 60

Explanation:

4 0
3 years ago
lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pu
Oksanka [162]

The work done by a constant force in a rectilinear motion is given by:

W=Fd\cos\theta

where F is the magnitude of the force, d is the distance and θ is the angle between the force and the displacement vector.

In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:

\begin{gathered} W=(17)(12)\cos0+(36)(12)\cos30 \\ W=578.123 \end{gathered}

Therefore, the total work done is 578.123 J and the answer is option E

6 0
1 year ago
The two pucks of equal mass did not move linearly (they came to a stop) after the collision due to the conservation of linear mo
weeeeeb [17]

Compared to the pucks given, the pair of pucks will rotate at the same rate.

Answer: Option A

<u>Explanation:</u>

The law of conservation of the angular momentum expresses that when no outer torque follows upon an article, no difference in angular momentum will happen.  At the point when an item is turning in a shut framework and no outside torques are applied to it, it will have no change in angular momentum.

The conservation of the angular momentum clarifies the angular quickening of an ice skater as she brings her arms and legs near the vertical rotate of revolution.  In the event, that the net torque is zero, at that point angular momentum is steady or saved.  

By twice the mass yet keeping the speeds unaltered, also twice the angular momentum's to the two-puck framework.  Be that as it may, we likewise double the moment of inertia. Since L=I \times \omega, the turning rate of the two-puck framework must stay unaltered.

4 0
3 years ago
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