Okay so the answer will be.
corrected question: A chemist adds 135mL of a 0.21M zinc nitrate solution to a reaction flask. Calculate the mass in grams of zinc nitrate the chemist has added to the flask. Round your answer to significant digits.
Answer:
5.37g
Explanation:
0.21M means ; 0.21mol/dm³
1dm³=1L , so we can say 0.21mol/L
if 0.21mol of Zinc nitrate is contained in 1L of water
x will be contained in 135mL of water
x= 0.21*135*10³/1
=0.02835moles
number of moles= mass/ molar mass
mass= number of moles *molar mas
molar mass of Zn(NO₃)₂=189.36 g/mol
mass= 0.02835 *189.36
mass=5.37g
Answer:
The answer to the question is 0.07 moles
Physical, since you are physically changing its appearance
Answer:
HClO4(aq) + H2O(l) ⇄ H3O+(aq) + ClO4-(aq)
Explanation:
When an acid dissolves in water, it will produce hydronium ion, H3O+ as the only positive ion.
perchloric acid, HClO4, being an acid will react with water, H2O to produce hydronium ion, H3O+ as shown below:
HClO4(aq) + H2O(l) ⇄ H3O+(aq) + ClO4-(aq)