Binary ionic compounds are named in the following pattern: metal followed by the nonmetal.
<span>C4H10 + 6.5 O2 ----> 4CO2 + 5H2O
2C4H10 + 13 O2 ----> 8CO2 + 10H2O
1. Count the C on the left (4), put a 4 where the C on the right.
2. Count the H on the left (1), you have two on the right, so you multimply this two by 5. Put the 5 in front of the H2O
3. Count the O on the right. You have 4*2 + 5 = 13. You have two on the left, so you need 6.5 on the left.
4. Now multiply everything on the equation by two so you have nice integer numbers.
5. check you have the same amount of everything on each side.
Example C: left 8, right 8, etc.
I hope this helps. :)</span><span>
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Explanation:
The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.
H2SO4
1 mol of H2SO4 contains 4 mol of O
x mol of H2SO4 would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of H2SO4
C2H4O2
1 mol of C2H4O2 contains 2 mol of O
x mol of C2H4O2 would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2
NaOH
1 mol of NaOH contains 1 mol of O
x mol of NaOH would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of NaOH
Answer: I have the same test message me
Explanation: it won’t let me share my answers
Answer: Deposition
Explanation:
