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neonofarm [45]
3 years ago
8

Balance this equation- Fe + O2 Fe3 O4

Chemistry
1 answer:
kherson [118]3 years ago
7 0
3Fe + 2O2 —- Fe3 + O4
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Which of these statements can be predicted with the help of science?
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Changes in Climate

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Ammonia gas has a molar mass of approximately 17 grams per mole. At 290k and 1.2 atm, a sample of ammonia has a volume of 3.7 L.
dlinn [17]

We have that for the Question, it can be said that the mass of Ammonia is

Mass_a=3.162grams

From the question we are told

<em>Ammonia </em>gas has a <u>molar</u> mass of approximately 17 <u>grams </u>per mole. At 290k and 1.2 atm, a sample of <em>ammonia </em>has a volume of 3.7 L. In <em>three </em>to five sentences, explain how you can find the mass of the <em>ammonia</em>. Then, given R= 0.0821L.atm/mol.k, calculate the mass.

Generally the equation for the   is mathematically given as

PV=nRT\\\\n=\frac{PV}{RT}\\\\n=0.186 moles\\\\

Now the mass of ammonia is

Mass_a=0.186*17\\\\Mass_a=3.162grams

Hence the mass of Ammonia is

Mass_a=3.162grams

For more information on this visit

brainly.com/question/23379286

3 0
3 years ago
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The activation energy for the gas phase isomerization of cyclopropane is 272 kJ. (CH2)3CH3CH=CH2 The rate constant at 718 K is 2
MrMuchimi
The Arrhenius equation relates activation energy to reaction rates and temperature:
ln (k2 / k1) = (E / R) * (1/T1 - 1/T2), where E is activation energy of 272 kJ, R is the ideal gas constant (we use the units of 0.0083145 kJ/mol-K for consistency, to cancel out the kJ unit), we let T1 = 718 K and k1 = 2.30 x 10^-5, and T2 = 753 K and k2 be the unknown.
ln (k2 / 2.30x10^-5) = (272 kJ / 0.0083145 kJ/mol-K) * (1/718 - 1/753)
k2 = 1.91 x 10^-4 /s

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its     C) decreased precipitation

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let me know when u find out plz because i would like to know as well its one of my chemistry qustions in an assiment. :)

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4 years ago
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