We have that for the Question, it can be said that the mass of Ammonia is
Mass_a=3.162grams
From the question we are told
<em>Ammonia </em>gas has a <u>molar</u> mass of approximately 17 <u>grams </u>per mole. At 290k and 1.2 atm, a sample of <em>ammonia </em>has a volume of 3.7 L. In <em>three </em>to five sentences, explain how you can find the mass of the <em>ammonia</em>. Then, given R= 0.0821L.atm/mol.k, calculate the mass.
Generally the equation for the is mathematically given as

Now the mass of ammonia is

Hence the mass of Ammonia is
Mass_a=3.162grams
For more information on this visit
brainly.com/question/23379286
The Arrhenius equation relates activation energy to reaction rates and temperature:
ln (k2 / k1) = (E / R) * (1/T1 - 1/T2), where E is activation energy of 272 kJ, R is the ideal gas constant (we use the units of 0.0083145 kJ/mol-K for consistency, to cancel out the kJ unit), we let T1 = 718 K and k1 = 2.30 x 10^-5, and T2 = 753 K and k2 be the unknown.
ln (k2 / 2.30x10^-5) = (272 kJ / 0.0083145 kJ/mol-K) * (1/718 - 1/753)
k2 = 1.91 x 10^-4 /s
let me know when u find out plz because i would like to know as well its one of my chemistry qustions in an assiment. :)