Answer:
See explanation below.
Step-by-step explanation:
Assuming the following function:

Where y represent the sales and t the years after a particular model is introduced.
For this case if we find the domain for this function we have this:
Since the neatural log for negative numbers or 0 is not defined.
So then 
And the range on this case is all the possible reals.
The sales are equal to 0 when:

If we exponential both sides we got:


So then the x intercept is
. We don't have y intercept since the function not touch the y axis.
And we don't have a relative maximum or minimum since the function is increasing over the interval of all the reals.
The plot of the function is on the figure attached.