Answer : The specific heat of the substance is 0.0936 J/g °C
Explanation :
The amount of heat Q can be calculated using following formula.

Where Q is the amount of heat required = 300 J
m is the mass of the substance = 267 g
ΔT is the change in temperature = 12°C
C is the specific heat of the substance.
We want to solve for C, so the equation for Q is modified as follows.

Let us plug in the values in above equation.


C = 0.0936 J/g °C
The specific heat of the substance is 0.0936 J/g°C
This question provides us –
- Weight of
is = 47 g - Volume, V = 375 mL
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- Molar Mass of
–


<u>Using formula</u> –






- Henceforth, Molarity of the solution is = 1.7M
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Answer:
33300J
Explanation:
Given parameters:
Mass of ice = 100g
Unknown:
Amount of energy = ?
Solution:
This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.
So;
H = mL
m is the mass
L is the latent heat of melting ice
Now, insert the parameters and solve;
H = mL
mass from gram to kilogram;
100g gives 0.1kg
H = 0.1 x 3.33 x 10⁵ = 33300J
C is the answer I’m pretty sure