Answer:
not a reason? if you ask a reason ,i can say An actual yield is the mass of a product actually obtained from the reaction. It is usually less than the theoretical yield. The reasons for this include:
-->incomplete reactions, in which some of the reactants do not react to form the product
practical losses during the experiment
->side reactions (unwanted reactions that compete with the desired reaction)
->reversible reactions
->impurities in reactants
but you asked for not reason then it can be anything lul, like balanced chemical equation, rate of reaction and etc etc ✌️;)
<h3>
Answer:</h3>
P₂ = 0.67 atm
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Chemistry</u>
<u>Gas Laws</u>
Boyle's Law: P₁V₁ = P₂V₂
- P₁ is pressure 1
- V₁ is volume 1
- P₂ is pressure 2
- V₂ is volume 2
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] P₁ = 2.02 atm
[Given] V₁ = 4.0 L
[Given] V₂ = 12.0 L
[Solve] P₂
<u>Step 2: Solve</u>
- Substitute in variables [Boyle's Law]: (2.02 atm)(4.0 L) = P₂(12.0 L)
- [Pressure] Multiply: 8.08 atm · L = P₂(12.0 L)
- [Pressure] [Division Property of Equality] Isolate unknown: 0.673333 atm = P₂
- [Pressure] Rewrite: P₂ = 0.673333 atm
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>
0.673333 atm ≈ 0.67 atm
Unlikely. It's unlikely for ammonium ion 
to accept a proton 
and act as a Bronsted-Lowry Acid.
<h3>Explanation</h3>
What's the definition of Bronsted-Lowry acids and bases?
- Bronsted-Lowry Acid: a species that can donate one or more protons in a reaction.
- Bronsted-Lowry Base: a species that can accept one or more protons
Ammonium ions are positive. Protons are also positive.
Positive charges repel each other, which means that it will be difficult for to accept any additional protons. As a result, it's unlikely that will accept <em>any</em> proton and act like a Bronsted-Lowry Base.
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