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ser-zykov [4K]
3 years ago
14

Write and simplify the expression for the area of a rectangle with a width of 3 inches and a length that is 8 inches more than x

Mathematics
1 answer:
meriva3 years ago
4 0
3(x+8)
You know that area of a rectangle is length x width. The width you know is 3 and the length is whatever x is plus 8 more inches, therefore it is x+8.
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Brandon buys a radio for $45.29 in a state where the sales tax is 7%. how much does he pay in taxes?
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Answer:

$3.18 in taxes

Step-by-step explanation:

5 0
3 years ago
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PLS PLS HELP, I DONT WANT TO FAIL!!
Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0
1 year ago
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Ugo [173]
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4 0
3 years ago
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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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18+12 is 30 and 30/6 is 5so the second one is 5'

if you want me to clarify more please comment

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3 years ago
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pshichka [43]

Answer: 462


Step-by-step explanation:

943-481

Answer=462

6 0
3 years ago
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