Answer:
a) 
Explanation:
a) the cross-sectional area of the hose would be the square of radius times pi. And since the sectional radius is half of its diameter d. We can express the cross-sectional area A1 in term of diameter d1

Oooooo, that statement is not true. Countries create quotas and tariffs to <em>LIMIT</em> the volume of trade with other countries, including their neighbors.
Answer:
a = 8.951 m/s²
Explanation:
given,
angle = 0.52 radians
μ_s = 0.84
μ_k = 0.48
acceleration = ?
using
F + f = m a
mg sin θ + μk mg cos θ = m a
a = g sin θ + μk g cos θ
a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52
a = 4.869 + 4.082
a = 8.951 m/s²
the magnitude of acceleration is a = 8.951 m/s²
On the dog's return trip (between <em>t</em> = 10 and <em>t</em> = 12.5 seconds), the slope of the position function is steeper than during the first 5 seconds, which means the dog ran home faster. The only option that captures this is D.
You can check to make sure that the dog indeed runs twice as fast on the return trip. The slope of the position function during the first 5 seconds is
(change in position) / (change in time) = (5 - 0) / (5 - 0) = 5/5 = 1
while during the return trip, it is
(0 - 5) / (12.5 - 10) = -5/2.5 = -2
Ignoring the sign (which only indicates the direction in which the dog was running), we see that the dog's speed on the return trip was indeed twice as high as during the first 5 s.
<span>The answer is Multichannel, single phase. </span>Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop a Multichannel, single phase queuing system line structure concerning machine breakdowns. It is <span>Multiple
servers, one phase of service.</span>