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prisoha [69]
3 years ago
6

A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.52 radians with the

horizontal. The frictional coefficients between the crate and plane are (\muμs = 0.84, \muμk = 0.48 ). What is the magnitude of the acceleration (in meters/second2) of this crate as it slides up the incline?
Physics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

a = 8.951 m/s²

Explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

acceleration = ?

using

F +  f = m a

mg sin θ +  μk mg cos θ = m a

a = g sin θ  + μk g cos θ

a = 9.8 x  sin 0.52 + 0.48 x 9.8 x  cos 0.52

a = 4.869 + 4.082

a = 8.951 m/s²

the magnitude of acceleration is a = 8.951 m/s²

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Burka [1]

Answer:

This is the information I can provide. I hope it helps

Explanation:

Frequency is measured in units of hertz (Hz) which is equal to one occurrence of a repeating event per second. The period is the duration of time of one cycle in a repeating event, so the period is the reciprocal of the frequency.

7 0
3 years ago
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A man attempts to push a 19.8 kg crate across a warehouse floor. He slowly increases the force until the crate starts to move at
VARVARA [1.3K]

Answer:

 μ = 0.18

Explanation:

Let's use Newton's second Law, the coordinate system is horizontal and vertical

Before starting to move the box

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     N-W = 0

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     fr = μ N

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At the limit point just before starting the movement

     F = μ m g

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calculate

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7 0
3 years ago
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7. Un bloque de 700 N se encuentra sobre una viga uniforme de 200 N y 6 m de longitud. El bloque está a una distancia de 1 m del
GrogVix [38]

Answer:

 x =  0.176 m

Explanation:

For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.

Let's use trigonometry to decompose the tension

      sin 60 = T_{y} / T

      T_{y} = T sin 60

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we apply the equation

       ∑ τ = 0

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the length of the bar is L = 6m

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let's calculate

let's use the maximum tension that resists the cable T = 900 N

             x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)

             x = (4676 - 5880) / 6860

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Therefore the block can be up to 0.176m to keep the system in balance.

5 0
3 years ago
We now have two tappers that are tapping the surface of the water together. They are tapping in sync (both are hitting the surfa
ollegr [7]

Answer:

The cork moves up and down.

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The cork moves up and down because of the waves produce due to tapping the surface of water. The cork experience movement due to placed on the water surface so when the wave passes through the medium by tapping of water, movement of cork also occur. Cork has high volume and lower mass so it floats on the water surface and experience movement due to waves.

5 0
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11. A 3.8 kg object is lifted 12 meters. Approximately how much work is performed during the lifting?
Mademuasel [1]
Hope this answers your question!! Ask any help at anytime
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