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prisoha [69]
3 years ago
6

A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.52 radians with the

horizontal. The frictional coefficients between the crate and plane are (\muμs = 0.84, \muμk = 0.48 ). What is the magnitude of the acceleration (in meters/second2) of this crate as it slides up the incline?
Physics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

a = 8.951 m/s²

Explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

acceleration = ?

using

F +  f = m a

mg sin θ +  μk mg cos θ = m a

a = g sin θ  + μk g cos θ

a = 9.8 x  sin 0.52 + 0.48 x 9.8 x  cos 0.52

a = 4.869 + 4.082

a = 8.951 m/s²

the magnitude of acceleration is a = 8.951 m/s²

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