Answer:
2.1 m/s
Explanation:
Momentum is conserved, so:
m₁ u₁ + m₂ u₂ = (m₁ + m₂) v
(9.1 kg) (6.6 m/s) = (9.1 kg + 19.3 kg) v
v = 2.1 m/s
The rock would be at a point 12 m from water at a time <u>4.8 s</u>.
Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.

Use the equation of motion,

The rock falls under the acceleration due to gravity, directed down wards.
Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.

Solve the quadratic equation for t.

Taking only the positive value,

After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.
FOCAL LENGTH = 9.5cm
i° e° d°
30 43 69
40 41 61
45 39 56
50 37 48
65 41 37
plot a graph of d° against i°
from the graph Determine;
(i) the minimum deviation and the corresponding angle of incidence
(ii) the maximum deviation and the corresponding angle of incidence
n=sin(A+D÷2)÷(sinA÷2)
Determine the error in n and explain why it is not advisable to use small values of i° in performing this experiment.
Answer:
1: body of significant size
Explanation:
Hopefully this helps!
1) Current
2) Atoms
3) Wire
4) Negative
5) Neutron
6) Shock
7) Switch
8) Static
9) Volt
10) Battery
11) Dam
12) Thomas Edison
13) Benjamin Franklin
14) Alessandro Volta
15) Michael Faraday
I would say that these would be your correct answers, btw I'm doing something that is close to the same right now
Hope this helps :)