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zhannawk [14.2K]
3 years ago
13

Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop which type of queuing syste

m line structure concerning machine breakdowns? single channel, single phase single channel, multiphase multichannel, single phase multichannel, multiphase none of the above
Physics
1 answer:
muminat3 years ago
7 0
<span>The answer is Multichannel, single phase.  </span>Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop a  Multichannel, single phase queuing system line structure concerning machine breakdowns.  It is <span>Multiple servers, one phase of service.</span>
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3 years ago
g Calculate the maximum wavelength of light that will cause the photoelectric effect for potassium. Potassium has work function
Ivahew [28]

Answer:

λ = 5.4196 10⁻⁷m,  λ = 541.96 nm    this is green ligh

Explanation:

The photoelectric effect was explained by Eintein assuming that the light was made up of particles called photons and these collided with the electrons taking them out of the material.

 

                     K = h f -Ф

where K is the kinetic energy of the ejected electrons, hf is the energy of the light quanta and fi is the work function of the material.

The speed of light is related to wavelength and frequency

                   c = λ / f

                  f = c /λ

we substitute

                K = h c / λ - Φ

for the case that they ask us the kinetic energy of the electons is zero (K = 0)

                 h c / λ = Ф

                λ = h c / Ф

we calculate

                 λ = 6.63 10⁻³⁴  3 10⁸ / 3.67 10⁻¹⁸

                 λ = 5.4196 10⁻⁷m

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3 years ago
How many calories you need per day to maintain your current weight.
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3 0
3 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
frozen [14]

Answer:

Their final velocity is 0.103 m/s

Explanation:

Given;

mass of the first car, m₁ = 130,000 kg

mass of the second car, m₂ = 115,000 kg

initial velocity of the first car, u₁ = 0.300 m/s

initial velocity of the second car, u₂ = -0.120 m/s

Let their final velocity, = v (since they were coupled together, they will have common final velocity)

Apply the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(130,000 x 0.3) + (115,000 x -0.12) = v(130,000 + (115,000)

39000 -13800 = 245,000v

25200 = 245,000v

v = 25200 / 245,000

v = 0.103 m/s

Therefore, their final velocity is 0.103 m/s

6 0
3 years ago
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