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zhannawk [14.2K]
3 years ago
13

Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop which type of queuing syste

m line structure concerning machine breakdowns? single channel, single phase single channel, multiphase multichannel, single phase multichannel, multiphase none of the above
Physics
1 answer:
muminat3 years ago
7 0
<span>The answer is Multichannel, single phase.  </span>Machine breakdown and repair in a twelve machine factory having three repair mechanics would develop a  Multichannel, single phase queuing system line structure concerning machine breakdowns.  It is <span>Multiple servers, one phase of service.</span>
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A man applies a force of 100 N to a rock for 60 seconds, but the rock does not move what is the amount of work done by the man o
Art [367]
600. I forgot the measurement. but 600 is correct
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3 years ago
Q 19.23: A proton is initially moving at 3.0 x 105 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude
DENIUS [597]

Answer:

The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

Explanation:

Given;

initial velocity of proton, v_p_i = 3 x 10⁵ m/s

distance moved by the proton, d = 3.5 m

electric field strength, E = 120 N/C

The kinetic energy of the proton at the end of the motion is calculated as follows.

Consider work-energy theorem;

W = ΔK.E

W =K.E_f - K.E_i

where;

K.Ef is the final kinetic energy

W is work done in moving the proton = F x d  = (EQ) x d = EQd

K.E_f =EQd + \frac{1}{2}m_pv_p_i^2

m_p \ is \ mass \ of \ proton = 1.673 \ \times \ 10^{-27} kg \\\\Q \ is \ charge \ of \ proton = 1.6 \times 10^{-19} C

K.E_f = 120\times 1.6 \times 10^{-19} \times 3.5   \ + \ \frac{1}{2}(1.673\times 10^{-27})(3\times 10^5)^2 \\\\

K.E_f = 6.72\times 10^{-17} \ + \ 7.53 \times 10^{-17} \\\\K.E_f = 14.25 \times 10^{-17} J\\\\K.E_f = 1.425\times 10^{-16} \ J

Therefore, the kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

3 0
3 years ago
What is 28 degrees Celsius converted to Fahrenheit?
torisob [31]
28 degrees celsius converts to 82.4 degrees in Fahrenheit :) 
3 0
3 years ago
Read 2 more answers
The angular separation of two stars is 0.1 arcseconds and you photograph them with a telescope that has an angular resolution of
gizmo_the_mogwai [7]

Answer:

Will see them as only one star

Explanation:

Solution:

- The angular resolution of a telescope means the minimum quantity that can be visualized. Since their angular separation ( 0.1 arcseconds ) is smaller than the telescope's angular resolution (1 arcseconds ), your photograph will seem to show only one star rather than two.

7 0
3 years ago
IP A spark plug in a car has electrodes separated by a gap of 6.5×10−2 in . To create a spark and ignite the air-fuel mixture in
emmainna [20.7K]

Answer:

a.) V=5283.2 \ V

b.) V=4064\ V

Explanation:

<u>Electric Field and Potential Difference</u>

There are several conditions that must be met for a spark to be created into an air gap. Once the physical conditions are fixed, a minimum electric field is necessary for the spark to be initiated. Let s be the separation between the electrodes and V their potential difference. The electric field is

a.)

\displaystyle E=\frac{V}{s}

Solving for V

V=E.s

The separation is

s= 5.5\cdot 10^{-2}\ in=0.001651 \ m

Thus the potential difference is

V=3.2\cdot 10^{6}\ V/m\times 0.001651 \ m

V=5283.2 \ V

b.) If the separation was greater, the applied voltage needs to be greater if the electric field has to be constant. One possible measure to keep electrodes as close as possible is to build them as sharp edges. It gives the spark an easier path to travel to.

If the separation is 0.05 inches =0.00127 m

V=3.2\cdot 10^{6}\ V/m\times 0.00127 \ m

V=4064\ V

7 0
3 years ago
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