<span>=1330 ft^2 x (1m^2/3.25 ft^2)
=124 m^2
</span>
Answer:
light reflects off the objects and enter our eyes
Answer:
43.75 miles must a person walk to utilize the energy in (“burn”) a pound of fat.
Explanation:
3,500 calories are present in 1 pound of the fat.
Thus, given that:
<u>4 calories are burnt in 1 minute of walking.</u>
So,
1 calories are burnt in 1/4 minute of walking.
Or,
<u>1 calories are burnt in 0.25 minute of walking.</u>
Thus,
<u>3500 calories are burnt in 0.25*3500 minutes of walking</u>
Minutes of walking needed to burn 3500 calories = 875 minutes.
Also, given that:
<u>20 minutes of walking covers 1 mile.</u>
<u>1 minute of walking covers 1/20 mile.</u>
So,
<u>875 minutes of walking covers (1/20)*875 mile.</u>
<u>43.75 miles must a person walk to utilize the energy in (“burn”) a pound of fat.</u>
Answer:
(i) The maximum acceleration upward is 2.02 m/s².
(ii) The maximum acceleration downward is 1.39 m/s².
Explanation:
Let a be the maximum acceleration of the elevator.
The mass of the person at ground is 150 lb. We have to convert the mass into kg,
1 lb = 0.453592 kg
150 lb = 68 kg
170 lb = 77 kg
120 lb = 54 kg
(i) The person experience a force due to Earth's gravity in the downwards direction. The magnitude of this force is:
F₁ = mg = 68 x 9.8 = 666.4 N
The weight of the person decreases as the elevator is moving upwards. So, the force experienced by the person in this case due to gravity is:
F₂ = 54 x 9.8 = 529.2 N
Applying Newton's force equation;
(F₁ - F₂) = ma
(666.4 - 529.2) = 68 x a
a = 2.02 m/s²
(ii) The weight of the person increases as the elevator is moving downwards. So, the force experienced by the person in this case due to gravity is:
F₂ = 77 x 9.8 = 754.6 N
Applying Newton's force equation;
(F₁ - F₂) = ma
(666.4 - 754.6) = 68 x a
a = -1.30 m/s²
Answer:
oh 50 points! how did you do it??!?!?!?! I see up to 8 points only
