All categories

3 years ago

A card is drawn at random from an ordinary deck of 52 playing cards. find the probability that it is:

1 answer:

amm18123 years ago

3 0

A 4/52 7.69%
b 1/52 1.92%
c 2/52 3.84%
d 13/52 25.00%
e 39/52 75.00%.
f 16/52 30.76%
g 3/52 5.76%.
FRACTIONAL AND PERCENTAGE ANSWERS

You might be interested in

Ryan decided to ride his bicycle X times around the neighborhood. His best friend

WITCHER [35]

5x + 8

easyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

3 0

3 years ago

Matteo is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli

natka813 [3]

Answer: (1.5, 0)

Step-by-step explanation:

Given : The shape of his satellite can be modeled by $y^2=6x$ where x and y are modeled in inches.

Now,the given equation $y^2=6x$ is a equation of parabola.

Here, coefficient of x is positive, hence the parabola opens rightwards.

On comparing this equation with standard equation $x^2=4mx$ , we get

$4m=6\\\Rightarrow\ m=\frac{6}{4}=1.5$

In standard equation, coordinates of focus=(m,0)

Thus for given equation coordinates of focus=(1.5,0)

4 0

3 years ago

Read 2 more answers

What is 6 more than 7 times a number is 41

son4ous [18]

the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

so x =5.9

8 0

3 years ago

Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.

Romashka [77]

Answer:

(3,7) (7,3) (−1,14) (0,1) (12,25)

(5,11) (0,12) (1,8) (12,0) (−1,−1)

Step-by-step explanation:

We have the following function:

$y = 2x+1$ .

We are going to check if each ordered pair is a solution.

(3,7)

If when $x = 3, y = 7$ , it is a solution.

$y = 2x + 1 = 2(3) + 1 = 7$

This ordered pair is a solution.

(7,3)

If when $x = 7, y = 3$ , it is a solution.

$y = 2x + 1 = 2(7) + 1 = 15$

This ordered pair is not a solution.

(-1,14)

If when $x = -1, y = 14$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is not a solution.

(0,1)

If when $x = 0, y = 1$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is a solution.

(12,25)

If when $x = 12, y = 25$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is a solution.

(5,11)

If when $x = 5, y = 11$ , it is a solution.

$y = 2x + 1 = 2(5) + 1 = 11$

This ordered pair is a solution.

(0,12)

If when $x = 0, y = 12$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is not a solution.

(1,8)

If when $x = 1, y = 8$ , it is a solution.

$y = 2x + 1 = 2(1) + 1 = 3$

This ordered pair is not a solution.

(12,0)

If when $x = 12, y = 0$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is not a solution.

(-1,-1)

If when $x = -1, y = -1$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is a solution.

3 0

3 years ago

What is 5 to the power of 5 - 9 (200 divided by 4) - (10x90) divided by 5 - (4 to the power of 4) x 5 + 156 - 256

yanalaym [24]

5^5-9(200/4)-(10*90)/5-4^4(5)+156-256

= 3125-9( 200/4)-(10*90)/5-(4^4)(5)+156-256

= 3125-(9)(50)- (10*90)/5-(4^4)(5)+156-256

= 3125-450- (10*90)/5-(4^4)(5)+156-256

= 2675-(10*90)/5-(4^4)(5)+156-256

= 2675 - 900/5 - (4^4)(5)+156-256

= 2675 - 180 - (4^4)(5)+156-256

= 2495 - (4^4)(5)+156-256

= 2495 - 1280 + 156 -256

= 1215 + 156 - 256

= 1371 - 256

= 1115

I hope that's help , please if you have question(s) just let me know !

6 0

3 years ago