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NemiM [27]
3 years ago
14

Why do polar substances dissolve in water?

Chemistry
2 answers:
SIZIF [17.4K]3 years ago
8 0

Polar molecules have " dipole dipole" force of attraction between the molecules consisting of partially positive ion and partially negetive ion.

Water is the best example of polar molecule, having strong "hydrogen bonding" between the atoms of Oxygen (-ve) and Hydrogen(+ve).

When any polar substance dissolved in water, it break down into +ve and -ve ions.

Because of the dipole dipole attraction polar molecules are soluble in water.

77julia77 [94]3 years ago
7 0

water molecules are attracted to polar molecules and surround them.
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Answer:

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2 years ago
A 45g Aluminum spoon (specific heat 0.88J/g degree Celcius) at 24 degrees Celcius placed in 180ml(180g) of coffee at 85 degrees
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Answer:

82 °C

Explanation:

Let the specific heat capacity of the coffee be that of water which is 4.2 J/g °C.

Now, at the final temperature, heat gained by Aluminum spoon ,Q equals heat lost by coffee, Q'.

Q = -Q'

Q = m₁c₁(T₂ - T₁) where m₁ = mass of aluminum spoon = 45 g, c₁ = specific heat of aluminum = 0.88 J/g °C, T₁ = initial temperature of aluminum spoon = 24 °C and T₂ = final temperature of aluminum spoon.

Q' = m₂c₂(T₂ - T₃) where m₂ = mass of coffee = 180 g, c₂ = specific heat of coffee = 4.2 J/g °C, T₃ = initial temperature of coffee = 85 °C and T₂ = final temperature of coffee.

So, Q = -Q'

m₁c₁(T₂ - T₁) = -m₂c₂(T₂ - T₃)

Making T₂ subject of the formula, we have

m₁c₁T₂ - m₁c₁T₁ = -m₂c₂T₂ + m₂c₂T₃

m₁c₁T₂ + m₂c₂T₂ =  m₂c₂T₃ + m₁c₁T₁

(m₁c₁ + m₂c₂)T₂ =  m₂c₂T₃ + m₁c₁T₁

T₂ =  (m₂c₂T₃ + m₁c₁T₁)/(m₁c₁ + m₂c₂)

substituting the values of the variables into the equation, we have

T₂ =  (180 g × 4.2 J/g °C × 85 °C + 45 g × 0.88 J/g °C × 24 °C )/(45 g × 0.88 J/g °C  + 180 g × 4.2 J/g °C)

T₂ =  (64260 J + 950.4 J)/(39.6 J/°C  + 756 J/°C)

T₂ =  65210.4 J/795.6 J/°C

T₂ =  81.96 °C

T₂ ≅  82 °C

8 0
2 years ago
A research team has just discovered a new element called Likhitium. Now they need to determine the average atomic mass in order
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The question is incomplete, the complete question is shown in the image attached to this answer.

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The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.

We obtain the relative atomic mass of Likhitium as follows;

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Hence the relative abundance of Likhitium is 139.13

6 0
2 years ago
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