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Leni [432]
4 years ago
9

Why is it important to use low flame when evaporating water from a recovered filtrate?

Chemistry
1 answer:
goldfiish [28.3K]4 years ago
4 0

It is important to use low flame when evaporating water from a recovered filtrate because then the water and filtrate will not spatter and the filtrate can also be recovered after evaporating water.

If flame is not low then water as well as got spatter so it is important to use low flame so that   the water and filtrate will not spatter.


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What happens when you touch two hot bowls made of different materials? The wooden and metal bowl are both at the same temperatur
Julli [10]

Answer:

Explanation:

Both metal and wooden bowls are at the same temperature . But wood is non-conductor of heat whereas metal is conductor of heat .

If we touch the wooden bowl , heat flows from hot to cold object . Since the finger is at higher temperature , heat flows from finger to wooden bowl . But , since wood is non conducting , it does not allow heat to be conducted through it . Hence very less heat will be conducted from our finger .

On the other hand , if we touch a metal bowl , heat flows from finger to the metal bowl , without any hinderance . Hence rate  of heat flow will be fast in case of metal bowl . As a result of it , we feel cool in touching metal bowl . This feeling will be absent in case of wooden bowl.

6 0
3 years ago
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
olya-2409 [2.1K]

Answer:

     strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

     X^{+} will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

                       E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)

So, strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

As reduction potential of the half cell X^{+}\mid X is higher than the reduction potential of the half cell Z^{3+}\mid Z therefore X^{+} will oxidize Z into Z^{3+} and itself gets converted into X.

     

5 0
3 years ago
What is the volume of 1g of ice in cm3?
Amanda [17]

Answer:

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

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What is the volume of 1g of ice in cm3?

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What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

What is the volume of 1g of ice in cm3?

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What is the volume of 1g of ice in cm3?

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Explanation:

3 0
4 years ago
Which of these is a pure substance
Galina-37 [17]

Both A and B are the answer.


4 0
3 years ago
A water treatment plant needs to maintain the pH of the water in the reservoir at a certain level. To monitor this, they take 2
Bumek [7]

Answer:

C.) 0.7967

Explanation:

Hello,

Normal distribution is used here as:

z=\frac{pH_{sample}-pH_{av}}{stand_{dev}*\sqrt{n} }

In this case, the sample's pH is 8.47, the average pH 8.5, standard deviation 0.22 and sample size 37, thus:

z= \frac{8.47-8.5}{0.22/\sqrt{37} }\\z=-0.8295

Now, based on the table for standard normal distribution which comes from a symmetric bell-like graph, the probability is 0.797 which matched with the C answer.

Best regards.

7 0
3 years ago
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