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givi [52]
3 years ago
6

Use your experimentally determined value of ksp and show,by calculations, that ag2cro4 should precipitate when 5ml of 0.004m agn

o3 are added to 5ml of 0.0024 m k2cro4.
Chemistry
1 answer:
Doss [256]3 years ago
8 0
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)

So, according to the balanced equation of the reaction:

and by using ICE table:

              Ag2CrO4(s)  → 2Ag+ (Aq) + CrO4^2-(aq)

initial                                     0                   0

change                              +2X                 +X

Equ                                       2X                   X

∴ Ksp = [Ag+]^2[CrO42-]

so by substitution:

∴ 3.83 x 10^-11 = (2X)^2* X

3.83 x 10^-11 = 4 X^3

∴X = 2.1 x 10^-4 

∴[CrO42-] = X = 2.1 x 10^-4 M

[Ag+] = 2X = 2 * (2.1 x 10^-4) 

                  = 4.2 x 10^-4 M

when we comparing with the actual concentration of [Ag+] and [CrO42-]

when moles Ag+ = molarity * volume

                               = 0.004 m * 0.005L

                               = 2 x 10^-5 moles
[Ag+] = moles / total volume
     
          = 2 x 10^-5 / 0.01L

          = 0.002 M

moles CrO42- = molarity * volume

                         = 0.0024 m * 0.005 L

                         = 1.2 x 10^-5 mol

∴[CrO42-] = moles / total volume

                 = (1.2 x 10^-5)mol / 0.01 L 

                 = 0.0012 M

by comparing this values with the max concentration that is saturation in the solution 

and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.

∴ the excess will precipitate out       
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3 years ago
The temperature of nitrogen is unknown when the gas occupies 100.0 mL at 99.10 kPa. If the gas is known to occupy 74.2 mL at 133
laiz [17]

Answer:

The unknown temperature is 304.7K

Explanation:

V1 = 100mL = 100*10^-3L

P1 = 99.10kPa = 99.10*10³Pa

V2 = 74.2mL = 74.2*10^-3L

P2 = 133.7kPa = 133.7*10³Pa

T2 = 305K

T1 = ?

From combined gas equation,

(P1 * V1) / T1 = (P2 * V2) / T2

Solving for T1,

T1 = (P1 * V1 * T2) / (P2 * V2)

T1 = (99.10*10³ * 100*10^-3 * 305) / (133.7*10³ * 74.2*10^-3)

T1 = 3022550 / 9920.54

T1 = 304.67K

T1 = 304.7K

3 0
3 years ago
Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of
Molodets [167]

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

  • V₁ / T₁ = V₂ / T₂

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

  • V₁= 600 mL
  • T₁= 360 K
  • T₂= 250 K

Substitute the values into the formula.

  • 600 mL /360 K = V₂ / 250 K

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

  • 250 K * 600 mL /360 K = V₂ / 250 K * 250 K
  • 250 K * 600 mL/360 K = V₂

The units of Kelvin cancel, so we are left with the units of mL.

  • 250 * 600 mL/360=V₂
  • 416.666666667 mL= V₂

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

  • 416.7 mL ≈V₂

The volume of the balloon at 250 K is approximately 416.7 milliliters.

5 0
2 years ago
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Semmy [17]

The property of mixture which describes a mixture are it can be separated by physical methods, it can appear different from different sources and it cannot be described by a chemical symbol or formula.

<h3>What are mixtures?</h3>

Mixtures are the compounds which are formed by the addition or combination of one or two elements or compounds.

As in the mixtures many states of matters are present and it will be filtered by using various physical methods, and it is not chemically shown by single chemical symbol or formula. Mixtures are also of two types:

  • Homogeneous mixtures are those in which equal compositions all over the volume is present.
  • Heterogeneous mixtures are those in which different composition all over the volume is present.

Hence options (1), (3) and (4) are correct.

To know more about mixtures, visit the below link:

brainly.com/question/24647756

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