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AleksAgata [21]
3 years ago
13

HELP ASAP!!

Chemistry
2 answers:
Ksju [112]3 years ago
4 0
109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

r-ruslan [8.4K]3 years ago
3 0

Answer:

The final volume reading in the graduated cylinder 62.7 ml.

Explanation:

Initial level of the water in graduated cylinder = 50 .0 ml

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Density of liquid = 8.56 g/mL

Mass of substance = 109 g

Putting values in above equation, we get:

8.56 g/mL=\frac{109 g}{\text{Volume of substance}}\\\\\text{Volume of substance}=12.7 mL

Volume occupied by the substance = 12.7 mL

Volume occupied by the substance will increase the volume of the water more by 12.7 ml.

The final volume reading in the graduated cylinder :

50 ml + 12.7 mL = 62.7 mL

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I am Lyosha [343]

Answer:

Hi, what are the problems on the lab?

Explanation:

5 0
3 years ago
Amestec 140 g solutie 9% cu 260 g solutie 12%, cu 60 g apa si x g solutie 4%. Ce c procentuala are noua solutie %?
Levart [38]

Answer:

PLEASE SOMEONE SOLVE THE QUESTION OR I'M GONNA FAIL

Explanation:

Purpose and Theory: A tablet of vitamin C contains the active ingredient called ascorbic acid (HC,H,0.).

Ascorbic acid is an organic acid which is a white power and is soluble in water.

In the following microtitration lab you will be grinding up a vitamin C tablet

, and using a 0.10 g sample of the

vitamin C powder, which will be dissolved in 20-40 mL of water. This solution will be used to determine the

quantity of ascorbic acid in a commercial vitamin C tablet.

Groups

Lab 2

# of Drops 1 or Drops 2 of Drops 3

96

91

94

Hadia

Data & Analysis:

Complete the missing information in the following data table [24]

1

2

3

Trial

Volume of NaOH (drops)

0 05mL drop

(NaOH (O 0050mol/L)

Volume of NaOH (ML)

Average Volume of NaOH (ml)

T I

O 0050

00050

00050

The balanced chemical reaction between ascorbic acid and sodium hydroxide is:

HC,H,O + NaOH NaC,H,Oye H,O,

1. Stoichiometrically calculate the mass (in grams) of ascorbic acid in the powdered sample. 

3 0
3 years ago
Consider the process used to produce iron metal from its ore.
Dmitry_Shevchenko [17]

Answer:

223.4 grams of iron can be produced from 2.5 moles of Fe2O3 and 6.0 moles of CO.

Explanation:

The balanced reaction is:

Fe₂O₃ (s) + 3 CO(g) → 2 Fe(s) + 3 CO₂ (g)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

  • Fe₂O₃: 1 mole
  • CO: 3 moles
  • Fe: 2 moles
  • CO₂: 3 moles

Being:

  • Fe: 55.85 g/mole
  • O: 16 g/mole
  • C: 12 g/mole

the molar mass of the compounds participating in the reaction is:

  • Fe₂O₃: 2*55.85 g/mole + 3*16 g/mole= 159.7 g/mole
  • CO: 12 g/mole + 16 g/mole= 28 g/mole
  • Fe: 55.85 g/mole
  • CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole

Then, by stoichiometry of the reaction, the following quantities participate in the reaction:

  • Fe₂O₃: 1 mole* 159.7 g/mole= 159.7 g
  • CO: 3 moles* 28 g/mole= 84 g
  • Fe: 2 moles* 55.85 g/mole= 111.7 g
  • CO₂: 3 moles* 44 g/mole= 132 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

So, first of all, you can apply the following rule of three: if by reaction stoichiometry 1 mole of Fe₂O₃ reacts with 3 moles of CO, then 2.5 moles of Fe₂O₃ react with how many moles of CO?

moles of CO=\frac{2.5 moles of Fe_{2} O_{3}*3 moles of CO }{1 mole of Fe_{2} O_{3}}

moles of CO= 7.5

But 7.5 moles of CO are not available, 6.0 moles are available. Since you have less moles than you need to react with 2.5 moles of Fe₂O₃, CO will be the limiting reagent.

Now you can apply the following rule of three: if by reaction stoichiometry 3 moles of CO produce with 111.7 grams of Fe, then 6 moles of CO will produce how much mass of Fe?

mass of Fe=\frac{6 moles of CO*111.7 grams of Fe}{3 moles of CO}

mass of Fe= 223.4 grams

<u><em>223.4 grams of iron can be produced from 2.5 moles of Fe2O3 and 6.0 moles of CO.</em></u>

5 0
3 years ago
For the reaction N2(g) + 3H2(g) 2NH3(g), what will happen if hydrogen gas was removed from the reaction mixture? There will be a
Hoochie [10]
This uses something called <span>Le Chatelier's principle. It states essentially that any stress put upon a system will be corrected.

In more simple terms, it means that in an equilibrium, such as the equation N2(g) + 3H2(g) <=> 2NH3(g), removing a reactant will cause the system to create more of said reactant to compensate for its loss, or adding excess reactant will cause the system to remove some of the added reactant. For future reference, the same principle applies to products in an equilibrium as well. 

In this case, hydrogen gas is a reactant, and hydrogen is being removed. According to </span><span>Le Chatelier's principle, the system will shift to create more hydrogen gas. In essence, it will shift in the direction of the hydrogen gas, so there will be a shift toward the reactants.

To clear something up, Keq will not change, as it is a constant value with constant conditions (such as temperature, pressure, etc.).</span>
7 0
3 years ago
What is the preasure in atmospheres of 20 mol of nitrogen gas in 36.2 L cylinder at 25 degrees C?
Savatey [412]

Answer:

P = 13.5 atm

Explanation:

Given that

No. of moles, n = 20 moles

Volume of nitrogen gas = 36.2 L

Temperature = 25°C = 298 K

We need to find the pressure of the gas. Using the ideal gas equation

PV = nRT

Where

R is gas constant, R=0.082057\ L-atm/K-mol

So,

P=\dfrac{nRT}{V}\\\\P=\dfrac{20\times 0.082057\times 298}{36.2 }\\\\P=13.5\ atm

so, the pressure of the gas is equal to 13.5 atm.

7 0
3 years ago
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