To know the number of atoms, it will be necessary to use the formula of avogadro. We calculate the number of moles then we can calculate the number of avogadro.
The molar mass of:
Phosphorus = 31g / mol
Mercury = 200 g / mol
Bismuth = 209 g / mol
Strontium = 87 g / mol.
The number of avogadro (N) is 6.023 10 ^ 23
n = m (mass) / M (molar mass)
number of atoms = n. N = m / M . N
number of phosphorus atoms = 5.14/31 . 6.023 10^23 = 9.98 10 ^ 22 atoms
Number of atoms of mercury = 2.16/200 . 6.023 10^23 = 6.5 10 ^ 21 atoms
Number of bismuth atoms = 1.8/209 . 6.023 10^23 = 5.18 10 ^ 21 atoms
Number of strontium atoms = 8.8 x 10-2 /87 . 6.023 10^23 = 6.09 10 ^ 20 atoms
By definitions of the prefixes in the metric system, the prefix milli- (abbreviated as m as in mg) indicates 1/1000 or 1 x 10^-3 of a gram. In this case, if a beaker has a mass of 77.275 g (I am assuming this is grams since most other units would make it too heavy or too light), we would multiply this by 1000 to convert it to milligrams. So 77.275 g = 77,275 mg.
Answer:
<h3>The answer is 0.32 moles</h3>
Explanation:
To find the number of moles given the number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
N = 1.93 × 10²³ particles
We have

We have the final answer as
<h3>0.32 moles</h3>
Hope this helps you
Answer:
...<em>when</em><em> </em><em>the</em><em> </em><em>pressure</em><em> </em><em>is</em><em> </em><em>high</em><em> </em><em>the</em><em> </em><em>equilibrium</em><em> </em><em>increases</em><em> </em><em>but</em><em> </em><em>when</em><em> </em><em>its</em><em> </em><em>low</em><em> </em><em>equilibrium</em><em> </em><em>decreases</em><em> </em><em>also</em><em> </em><em>in</em><em> </em><em>temperature</em><em> </em><em>the</em><em> </em><em>higher</em><em> </em><em>the</em><em> </em><em>temperature</em><em> </em><em>the</em><em> </em><em>high</em><em> </em><em>the</em><em> </em><em>equilibrium</em><em> </em><em>and</em><em> </em><em>viceversa</em><em> </em><em>is</em><em> </em><em>true</em><em> </em><em>but</em><em> </em><em>also</em><em> </em><em>in</em><em> </em><em>concentration</em><em> </em><em>its</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>case</em>