All categories

3 years ago

How the materials between a capacitors’ plates can change its capacitance

Physics

1 answer:

dem82 [27]3 years ago

4 0

Answer:

it helping

Explanation:

and helping aterials between a capacitors’ plates can change its capacitance

You might be interested in

A stargazer has an astronomical telescope with an objective whose focal length is 195 cm and an eyepiece whose focal length is 1

Colt1911 [192]

Answer:

The best angular magnification is

-375

Explanation:

Fe = Fo - L

From the question, (Fo) = 1.08 cm while (L) = 0.56cm

Thus, Fe = 1.08 - 0.56 = 0.52cm

Now, let's apply the angular magnification equation ;

M = - Di/Do

Where Di is the distance from the lens to the image and Do is the distance of the object to the lens.

In this question, Di is represented by f which is the distance from the lens to the image and it is f= 195cm

Also,Do is represented by Fe which is 0.52cm and it is the distance of the object to the lens.

Thus m = - f/fe = - 195/0.52 = - 375

6 0

3 years ago

Mike Powell holds the record for the long jump of 8.95 m, established in 1991. If he left the ground at an angle of 18.8°, what

maksim [4K]

Answer:

Explanation:

<u>Projectile Motion</u>

It's also known as 2D motion because the movement takes place in both axis x and y. The x-axis motion is at a constant speed since in absence of friction, no external force stops or accelerates the object. The y-axis motion is at variable speed, which is changed by the acceleration of gravity that makes the object to reach a maximum height and then go back to ground level.

The maximum horizontal distance reached (also called Range) is given by

$\displaystyle X_m=\frac{V_{o}^2sin2\theta}{g}$

Knowing that $\theta=18.8^o, X_m=8.95\ m$ , we solve for Vo

$\displaystyle V_o=\sqrt{\frac{gX_m}{sin2\theta}}$

$\displaystyle V_o=\sqrt{\frac{9.8\cdot 8.95}{sin(2\cdot 18.8^o)}}=12\ m/s$

Thus, the initial speed of Mike Powell was 12 m/s

7 0

3 years ago

If the spring constant is doubled, what value does the period have for a mass on a spring? A. The period would double by square

antoniya [11.8K]

Answer:

The period would decrease by sqrt(2)

Explanation:

The restoring force is given by,

F = -kx

According to Newton's second law of motion,

ma = -kx

ma + kx = 0

The time period is given by,

T = $\frac{2\pi }{\omega }$

Where $\omega$ is the angular velocity and it is given by,

$\omega$ = $\sqrt{\frac{k}{m} }$

Now if the spring constant is doubled then,

$k_{2} = 2k$

Thus,

$T_{2}$ = $\frac{2\pi }{\sqrt{\frac{2k}{m} } }$

$\frac{T_{2} }{T} = \frac{\frac{2\pi }{\sqrt{\frac{2k}{m} } }}{\frac{2\pi }{\sqrt{\frac{k}{m} } }}$

$\frac{T_{2} }{T} = \sqrt{\frac{k}{2k} } = \sqrt{\frac{1}{2} }$

$T_{2} = \frac{T}{\sqrt{2} }$

Thus, The period would decrease by sqrt(2).

Hence, option D is correct.

3 0

3 years ago

Read 2 more answers

Darina [25.2K]

Resolving vectors question. See diagram enclosed.

4 0

3 years ago

Find the mean of set values 12g 9g 13g 12g 20g 17g 15g

nalin [4]

${\huge{\boxed{\mathcal{\green{Answer}}}}} \\ \frac{12 + 9 + 13 + 12 + 20 + 17 + 15}{7} \\ = \frac{98}{7} \\ = 14 \\ {\huge{\boxed{\mathcal{\green{Hope \: it \: Helps}}}}}$

5 0

3 years ago