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scoundrel [369]
3 years ago
12

You construct a circuit containing some component C, along with other circuit elements. You want to simultaneously measure the c

urrent through C and the voltage across C while it remains connected to the rest of the circuit. Indicate where you would connect an ammeter (A) and a voltmeter (V) to perform these measurements. Fill any remaining gaps with wires as needed to complete the connection with the rest of the circuit.

Physics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

The position of the ammeter is in series down the component. While the voltmeter must be connected in parallel. Its position is the gap through the component C.

The positions of one or the other are indicated in the image.

Explanation:

An ammeter is defined as a device used to measure current. Its unit is the ampere. While a voltmeter is used in the measurement of the potential difference between two points. Its unit is the volt. The ammeter must be connected in series with the point at which the current is to be measured, while the voltmeter must be connected in parallel.

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The question is incomplete. The complete question is :

In a certain underdamped RLC circuit, the voltage across the capacitor decreases in one cycle from 5.0 V to 3.8 V. The period of the oscillations is 1.2 microseconds (1.2*10^-6). What is Q?

Solution :

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 $\frac{R}{L} = 457.3 \times 10^3$

Now, Q value $= \frac{1}{R}\sqrt{\frac{L}{C}}$

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                     $=\sqrt{(\frac{L}{R})^2 \times \frac{1}{LC}}$

              $\frac{1}{LC}=27.43 \times 10^{12}$

∴ $Q=\sqrt{\left(\frac{1}{457.3 \times 10^3}\right)^2 \times 27.43 \times 10^{12}}$

  $Q=\sqrt{131.166}$

      = 11.45

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