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Alenkasestr [34]
2 years ago
10

From your results on page 29, decide whether you are able to demonstrate that the masses of the 4 different baskets differ meani

ngfully. That is, do the baskets' masses differ by more than the range of measurement error that was obtained by repeatedly measuring the mass of one basket?
Physics
1 answer:
Gekata [30.6K]2 years ago
6 0

Yes, it was demonstrated that the masses of the 4 different baskets differ meaningfully.

If we compare the two ranges, the differences are significant because the error range for the same basket was less than the differences between different baskets.

The Error range is a measurement of the degree of uncertainty attached to a number and is defined as the difference between the greatest and lowest error values.

So, Yes the baskets masses differ by more than the range of measurement error that was obtained by repeatedly measuring the mass of one basket.

Learn more about Experimental Errors herehttps://brainly.com/question/17648352

#SPJ4

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Why is it important to be able to trace the pole connection on a meter back to the same type of pole at the electrical source?
lozanna [386]

Answer:

Explanation:

A grounded wire is sometimes strung along the tops of the towers to provide lightning protection.

In areas where the neutral is grounded or earthed, it is essential to endure that the neutral and the live or hot wires are not confused for each other.

When this happens, the fuses on the transformer will not operate unless the fault is very close to the transformer. The fuses in the consumer's intake box, will not operate.

6 0
3 years ago
How much heat is needed to warm 0.072kg of gold from 20 celsius and 90 celsius if the specific heat of gold 136 joules
dybincka [34]

Heat supplied to the gold will raise the temperature of the gold from 20 degree Celsius to 90 degree Celsius.

Mass of the gold (m) = 0.072 kg

Temperature change (ΔT) = 90 - 20 = 70 degree Celsius

Specific heat capacity of the gold (c) = 136 J/kg C

Heat supplied = m × c × ΔT

Heat supplied = 0.072 × 136 × 70

Heat supplied = 685.44 Joules

Hence, the heat supplied to the gold to raise the temperature from 20 degree Celsius to 90 degree Celsius = 685.44 Joules

5 0
3 years ago
A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the
ser-zykov [4K]

Answer:

The maximum length during the motion is L_{max} = 1.45m

Explanation:

From the question we are told that

           The mass  is  m =0.5 kg

            The vertical spring  length is  L = 1.10m

            The unstretched  length is  L_{un} = 1.30m

          The initial speed is v_i = 1.3m/s

          The new length of the spring L_{new} =  1.30 m

The spring constant k is mathematically represented as

                           k = -\frac{F}{y}

Where F is the force applied  = m * g = 0.5 * 9.8=4.9N

           y is the difference in weight which is   =1.10-0.50=0.6m

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

    Now  substituting values accordingly

                    k =  \frac{4.9}{0.6}

                       = 8.17 N/m

The  elastic potential energy is given as E_{PE} = \frac{1}{2} k D^2

  where D is this the is the displacement  

Since Energy is conserved the total elastic potential energy would be

             E_T = initial  \ elastic\ potential \ energy + kinetic \ energy

            E_T = \frac{1}{2} k D_{max}^2 =   \frac{1}{2} k D^2 + \frac{1}{2} mv^2

Substituting value accordingly

                \frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2

                4.085 * D_{max}^2 = 3.69

                 D^2_{max} = 0.9033

                D_{max} = 0.950m

So to obtain total length we would add the unstretched length

 So we have

                  L_{max} = 0.950 + 0.5 = 1.45m

                               

               

               

                 

                     

5 0
3 years ago
Read 2 more answers
Sort the length measurements in increasing order of magnitude from smallest to largest Drag each tile to the correct box Tiles S
wariber [46]

Answer:

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Explanation:

Given the following length measurement :

micrometer Kilometer decimeter centimeter nanometer dekameter.

Sorting in increasing order of magnitude from Smallest to Largest.

Expressing in terms of meters :

1 meter = 0.1 decameter

1 meter = 1 × 10^9 nanometer

1 meter = 1 × 10^2 centimeter

1 meter = 1 × 10^1 decimeter

1 meter = 0.001 kilometer

1 meter = 1 × 10^6 micrometers

Hence, arranging from Smallest to Largest :

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

3 0
3 years ago
Two charged spheres are 20cm apart and exert an attractive force of 6x10^-9 N on each other. What will be the force of attractio
Travka [436]
The force of attraction between 2 charged spheres can be explained by Coulomb's law,
It states the force of attraction is directly proportional to the magnitudes of the charges and inversely proportional to the square of the distance between the charges.

/F =  \frac{k q_{1}  q_{2} }{ r^{2} }
where F - force of attraction/repulsion
q₁ and q₂ - charges of the 2 spheres 
k - Coulomb's law constant
r - distance between the spheres

In the question given, the charges of the spheres remain constant in both instances, only distance changes. Therefore (kq₁q₂) = c which is a constant 
then F = c / r²
first instance 
6 x 10⁻⁹ N = c/ (20 cm)² ---1)
F = c/(10 cm)² --- 2)
2) / 1)
\frac{F}{6* 10^{-9} } =  \frac{400}{100}
F = 6 x 10⁻⁹ x 4
F = 2.4 x 10⁻⁸ N
8 0
3 years ago
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