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brilliants [131]
3 years ago
11

If the labor force of 155 million people is growing by 1.0 percent per year, how many new jobs have to be created each month to

keep unemployment from increasing?
Physics
1 answer:
dybincka [34]3 years ago
8 0

First let us compute for the total growth in population.

Growth = 155 million * 0.01

Growth = 1.55 million

 

Since there are 12 months in a year, therefore the new jobs every month should be:

new jobs per month = 1.55 million / 12

<span>new jobs per month = 0.129 million = 129,167 </span>

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the ratio of the energy per second radiated by the filament of a lamp at 250k to that radiated at 2000k, assuming the filament i
Naily [24]

Answer:

(a) \frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b) P =  0.816 Watt

Explanation:

(a)

The power radiated from a black body is given by Stefan Boltzman Law:

P = \sigma AT^4

where,

P = Energy Radiated per Second = ?

σ = stefan boltzman constant = 5.67 x 10⁻⁸ W/m².K⁴

T = Absolute Temperature

So the ratio of power at 250 K to the power at 2000 K is given as:

\frac{P_{250k}}{P_{2000k}}=\frac{\sigma A(250)^4}{\sigma A(2000)^4}\\\\\frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b)

Now, for 90% radiator blackbody at 2000 K:

P = (0.9)(5.67\ x\ 10^{-8}\ W/m^2.K^4)(1\ x\ 10^{-6}\ m^2)(2000\ K)^4

<u>P =  0.816 Watt</u>

7 0
3 years ago
n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnet
enot [183]

Answer:

The  corresponding  magnetic field is  

Explanation:

From the question we are told that

    The electric field amplitude is  E_o   =  611\  V/m

   

Generally the  magnetic  field amplitude is  mathematically represented as

              B_o  =  \frac{E_o }{c }

Where c is the speed of light with a constant value

         c = 3.0 *0^{8} \ m/s

So  

        B_o   =  \frac{611 }{3.0*10^{8}}

         B_o   =  2.0 4 *10^{-6} \  Vm^{-2} s

Since 1  T  is  equivalent to  V  m^{-2} \cdot  s

         B_o  =  2.0 4 *10^{-6} \ T

6 0
4 years ago
Ryan is driving home from work and notices a deer leaping onto the road about 25 m in front of his car. He immediately applies t
Anvisha [2.4K]

Answer:

mu = 0.56

Explanation:

The friction force is calculated by taking into account the deceleration of the car in 25m. This can be calculated by using the following formula:

v^2=v_0^2+2ax\\

v: final speed = 0m/s (the car stops)

v_o: initial speed in the interval of interest = 60km/h

    = 60(1000m)/(3600s) = 16.66m/s

x: distance = 25m

BY doing a the subject of the formula and replace the values of v, v_o and x you obtain:

a=\frac{v^2-v_o^2}{2x}=\frac{0m^2/s^2-(16.66m/s)^2}{2(25m)}=-5.55\frac{m}{s^2}

with this value of a you calculate the friction force that makes this deceleration over the car. By using the Newton second's Law you obtain:

F_f=ma=(1490kg)(5.55m/s^2)=8271.15N

Furthermore, you use the relation between the friction force and the friction coefficient:

F_f= \mu N=\mu mg\\\\\mu=\frac{F_f}{mg}=\frac{8271.15N}{(1490kg)(9.8m/s^2)}=0.56

hence, the friction coefficient is 0.56

6 0
3 years ago
The term used to describe the quantity of matter that a body possesses is:
barxatty [35]
The term used to describe the quantity of matter that a body possesses is mass.
7 0
3 years ago
What has highest frequency in electromagnetic spectrum color?
natulia [17]
In Electromagnetic spectrum, X-rays has very high frequency but gamma-rays has more than that. If you consider cosmic rays as an electromagnetic wave, then it would be highest energetic and has highest frequency.

In short, Your Answer is "Cosmic rays"

Hope this helps!
6 0
3 years ago
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