Answer:0.0144 tesla
Explanation:
Magnetic field strength is the same as Magnetomotive force
B= I/2πr
B=magnetic field strength
I=current
r=radius=0.15/2=0.75m
Area=πr2= 1.77m2
torqueT= NIABsin theta
B= T/NIABsin theta
B=0.135/1 * 5.3 * 1.77 *sin90
B=0.0144 tesla
Answer:
Explanation:
Answer:
Explanation:
Given that,
System of two particle
Ball A has mass
Ma = m
Ball A is moving to the right (positive x axis) with velocity of
Va = 2v •i
Ball B has a mass
Mb = 3m
Ball B is moving to left (negative x axis) with a velocity of
Vb = -v •i
Velocity of centre of mass Vcm?
Velocity of centre of mass can be calculated using
Vcm = 1/M ΣMi•Vi
Where M is sum of mass
M = M1 + M2 + M3 +...
Therefore,
Vcm=[1/(Ma + Mb)] × (Ma•Va +Mb•Vb
Rearranging for better understanding
Vcm = (Ma•Va + Mb•Vb) / ( Ma + Mb)
Vcm = (m•2v + 3m•-v) / (m + 3m)
Vcm = (2mv — 3mv) / 4m
Vcm = —mv / 4m
Vcm = —v / 4
Vcm = —¼V •i
Answer:
The power output of the oscillator is 0.350 watt.
Explanation:
Given that,
Diameter = 1.0 mm
Tension = 5.7 N
Frequency = 57.0 Hz
Amplitude = 0.54 cm
We need to calculate the power output of the oscillator
Using formula of the power

Put the value into the formula



Hence, The power output of the oscillator is 0.350 watt.
Answer:
60000N
Explanation:
acceleration is change in velocity
a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity
a = (0-60)/5 = -60/5= - 12m/s^2
here minus sign shows that body is decelerating and force is force of friction Now f = ma here f is force of friction m is mass and a is acceleration
f= 5000×- 12= -60000N
MINUS SIGN HERE SHOWS FORCE OF FRICTION
Hence force of friction is 60000N
Work is being done because picking up a cushion and putting it somewhere is the motion of doing something (work).