Answer:
- path differnce = 2.18*10^-6
- 1538 lines
Explanation:
- The path difference for the waves that produce the pattern of diffraction, is given by the following formula:
(1)
d: separation between slits = 0.50mm = 0.50*10^-3 m
θ: angle of a diffraction = 0.25°
Then, the path difference is:

- The maximum number of bright lines are calculated by using the following formula:
(2)
m: order of the bright
λ: wavelength = 650nm
The maximum bright is calculated for an angle of 90°:

The maxium number of bright lines are twice the previous result, that is, 1538 lines
Increase .... decrease .... presumably it's the "best shape" for a body which has been formed by the gravitational force
Answer:
the answer is static electricity
The coefficient of static friction is 0.234.
Answer:
Explanation:
Frictional force is equal to the product of coefficient of friction and normal force acting on any object.
So here the mass of the object is given as 2 kg, so the normal force will be acting under the influence of acceleration due to gravity.
Normal force = mass * acceleration due to gravity
Normal force = 2 * 9.8 = 19.6 N.
And the frictional force is given as 4.6 N, then

Coefficient of static friction = 4.6 N / 19.6 N = 0.234
So the coefficient of static friction is 0.234.
Answer:
288.2 K
Explanation:
= Volumetric expansion coefficient = 
= Initial temperature = 273.1 K
= Final temperature
= Original volume = 150 mL
Change in volume is given by

The temperature of the ethyl alcohol should be 288.2 K to reach 150 mL