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3 years ago

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Satellite in a circular orbit of radius r around planet x has an orbital period t. if planet x had one-fourth as much mass, the

orbital period of this satellite in an orbit of the same radius would be

1 answer:

postnew [5]3 years ago

7 0

<span>Satellite in a circular orbit of radius r around planet x has an orbital period t. if planet x had one-fourth as much mass, the orbital period of this satellite in an orbit of the same radius would be 2t</span>

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Classify each process according to whether it does or does not produce a new substance.

AlexFokin [52]

The processes under chemical change are: cooking an egg, fireworks exploding, and rusting of a metal tool.

The processes under physical change are: melting ice, evaporating puddle of water, and dissolving of salt in water.

Given:

The following process:

cooking an egg
melting ice
fireworks exploding
evaporating puddle of water
rusting of a metal tool
Dissolving of salt in water

To find:

The classify the processes in whether it does or does not produce a new substance.

Solution:

Chemical change is the change when a new substance is formed due to a change in the chemical composition of the substance.
Physical change is the change in which no change in chemical composition takes place and the identity of the substance remains the same.

Cooking an egg

Chemical change, due to change in atomic arrangement egg get solidified on cooking, a new substance is formed.

Melting ice

Physical change, change in the state of matter is taking from solid to liquid, no new substance is formed.

Firework exploding

Chemical change. formation of carbon dioxide gas and sound energy, anew substance formed

Evaporating puddle of water

Physical change, change in the state of matter is taking from liquid to gas, no new substance is formed.

Rusting of metal tool

Chemical change, formation of oxides on the surface of the metal tool due to reaction between air and metal, a new substance is formed.

Dissolving of salt in water

Physical change, ions of salt in the solid state are changing into aqueous ions with no formation of new substance, no new substance is formed.

The processes under chemical change are: cooking an egg, fireworks exploding, and rusting of a metal tool.

The processes under physical change are: melting ice, evaporating puddle of water, and dissolving of salt in water.

Learn more about physical change and chemical change here:

brainly.com/question/864557?referrer=searchResults

brainly.com/question/13316655?referrer=searchResults

7 0

3 years ago

What is the mechanical advantage of a pulley system

tatuchka [14]

Answer:

Pulleys accomplish 2 separate operations throughout the computer controlled additional benefit technologies listed elsewhere here.

Explanation:

If indeed the pulley would be connected to that same attachment point, these are named a corrected pendulum or perhaps a change in direction. Its job should be to reverse the trajectory of that same rope pull.
Unless the pulley would be connected to that same load, this same pulley seems to be a detachable as well as a mechanical additional benefit.

7 0

3 years ago

The value of a car after 5 years is a quantitative data. True or False

NeX [460]

Answer:

true

Explanation:

7 0

3 years ago

Read 2 more answers

An electron of mass 9.11×10−31 kgkg leaves one end of a TV picture tube with zero initial speed and travels in a straight line t

ki77a [65]

Explanation:

We will use the equations of constant acceleration to find out $a_{x}$ and time t.

As we know that the initial speed is zero. So

(a)

$v_{0x} = 0$

$x - x_{o} = 1.25$ × $10^{-2}$ m

$v_{x} = 3.3$ × $10^{6}$ m/s

$v^{2} _{x} = v^{2} _{x_{o} } + 2a_{x} (x - x_{o} )$

$a_{x} = \frac{v^{2} _{x} - v^{2} _{ox} }{2(x - x_{o}) }$

= $\frac{(3.3 * 10^{6})^{2} - 0 }{2(1.25 * 10^{-2}) }$

= 4.356× $10^{14}$ m/s²

(b)

$v_{x} = v_{ox} + a_{x}t$

$t = v_{x} - vo_{x}/a_{x}$

$t = \frac{3.00 * 10^{6} }{4.356*10^{14} }$ = 6.8870× $10^{-9}$ s

(c)

Σ $F_{x} = ma_{x}$

= (9.11× $10^{-31}$ )(4.356× $10^{14}$ m/s²)

= 3.968× $10^{-16}$ N

6 0

3 years ago

A 24 kg child slides down a 3.3-m-high playground slide. She starts from rest, and her speed at the bottom is 3.0 m/s.a. What en

Gelneren [198K]

Answer:

(a) Potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

(b) $U=668.16\ J$

Explanation:

Given:

mass of the child, $m=24\ kg$

height of the slide, $h=3.3\ m$

initial velocity of the child at the slide, $v_i=0 m.s^{-1}$

final velocity of the child at the bottom of slide, $v_f=3\ m.s^{-1}$

(a)

∴The initial potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

Initial potential energy:

$PE=m.g.h$

$PE=24\times 9.8\times 3.3$

$PE=776.16\ J$

Kinetic energy at the bottom of the slide:

$KE=\frac{1}{2} m.v^2$

$KE= 0.5\times 24\times 3^2$

$KE= 108\ J$

(b)

Now, the difference in the potential and kinetic energy is the total change in the thermal energy of the slide and the seat of her pants.

This can be given as:

$U=PE-KE$

$U=776.16-108$

$U=668.16\ J$

4 0

3 years ago