Waves with a higher frequency have a ______ wavelength and ____

A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 21.0 N/m. The

mestny [16]

Answer:

a. Δx = 2.59 cm

Explanation:

mb = 0.454 kg , mp = 5.9 x 10 ⁻² kg , vp = 8.97 m / s , k = 21.0 N / m

Using momentum conserved

mb * (0) + mp * vp = ( mb + mp ) * vf

vf = ( mp / mp + mb) * vp

¹/₂ * ( mp + mb) * (mp / mp +mb) ² * vp ² = ¹/₂ * k * Δx²

Solve to Δx '

Δx = √ ( mp² * vp² ) / ( k * ( mp + mb )

Δx = √ ( ( 5.9 x 10⁻² kg ) ² * (8.97 m /s) ² / [ 21.0 N / m * ( 5.9 x10 ⁻² kg + 0.454 kg ) ]

Δx = 0.02599 m ⇒ 2.59 cm

8 0

3 years ago

An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of w

allochka39001 [22]

Answer:

$Q_a=330 cal$

$Q_w=6000cal$

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

$Q_c=M_c *C_c*( \triangle T)$

Therefore imputing variables we have

$Q_a=50g *0.22*50-20$

$Q_a=330 cal$

b) Heat energy on water

Generally the formula for mathematically solving heat gain

$Q_w=M_w *C_w*( \triangle T)$

Therefore imputing variables we have

$Q_w=200 *1* 50-204$

$Q_w=6000cal$

7 0

3 years ago

A car traveling 60 km/h can brake to a stop within a distance d of 20 m. If the car is going twice as fast, 120 km/h, what is it

lubasha [3.4K]

40m oaivbapiudrvbusfbdpiugahsfpuioapvbrh

4 0

2 years ago

A hot air balloon is hovering in the air when it drops a 40 Kg food package to some lost golfers. If the package is dropped from

UNO [17]

We can calculate this with the law of conservation of energy. Here we have a food package with a mass m=40 kg, that is in the height h=500 m and all of it's energy is potential. When it is dropped, it's potential energy gets converted into kinetic energy. So we can say that its kinetic and potential energy are equal, because we are neglecting air resistance:

Ek=Ep, where Ek=(1/2)*m*v² and Ep=m*g*h, where m is the mass of the body, g=9.81 m/s² and h is the height of the body.

(1/2)*m*v²=m*g*h, masses cancel out and we get:

(1/2)*v²=g*h, and we multiply by 2 both sides of the equation

v²=2*g*h, and we take the square root to get v:

v=√(2*g*h)

v=99.04 m/s

So the package is moving with the speed of v= 99.04 m/s when it hits the ground.

5 0

3 years ago

The standard wave format for any wave is

Novay_Z [31]

The standard wave format for any wave is transverse wave

8 0

3 years ago

Waves with a higher frequency have a ______ wavelength and _____ energy. *

Waves with a higher frequency have a __ wavelength and _ energy. *