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Ulleksa [173]
3 years ago
15

Consider a ball in projectile motion under gravitational force so that it is has motion in both the vertical and horizontal dire

ctions. The effects of air friction may be ignored. When the ball reaches the highest point in its trajectory, what can be said about the magnitudes of the ball's velocity and acceleration vectors? Select the correct answer
a. The horizontal components of both the velocity and acceleration are zero.
b. The magnitude of velocity is zero, but the acceleration is a constant
c. The magnitudes of both velocity and acceleration are zero
d. The magnitude of acceleration is zero but the ball has a positive velocity
e. The magnitude of velocity is at its minimum nonzero value, but the magnitude of acceleration is a constant
Physics
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

e.)The magnitude of velocity is at its minimum nonzero value, but the magnitude of acceleration is a constant

Explanation:

The speed of horizontal projectile is always constant for the duration of its flight. The reason behind this is that immediately the object is launched, the horizontal forces acting on the projectile is recorded as zero, and here the air resistance is negligible because because it is very minute therefore, horizontally projectile always travel at a constant speed.

At the same time, There is unbalanced forces directly acting on the ball and this will make the ball to accelerate into downward direction, Hence, the motion of vertical projectile is supported by the force of gravity. Since the vertical speed is not constant, acceleration is constant

Therefore, the magnitudes of the ball's is at the minimum nonzero value and velocity and acceleration vectors is constant.

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prohojiy [21]

Answer:

a

Explanation:

because it taken the rock more time to hit the water

8 0
4 years ago
1. A student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.
Snezhnost [94]

Explanation:

(a) Displacement of an object is the shortest path covered by it.

In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag.  She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.

0.4 miles = 0.64 km

displacement = 0.7-0.3+0.64 = 1.04 km

(b) Average velocity = total displacement/total time

t = 15 min = 0.25 hour

v=\dfrac{1.04\ km}{0.25\ h}\\\\v=4.16\ km/h

Hence, this is the required solution.

8 0
4 years ago
he primary coil of a transformer is connected to 240 V ac supply. The induced secondary voltage is 60 V. If the ac current in th
vovikov84 [41]

Answer:

Secondary current is  8A

Explanation:

Data :

Primary supply = Vp = 240 V

Secondary supply = Vs = 60V

Primary current = Ip = 2A

Secondary current = Is = ?

Formula  :     Vp × Ip = Vs × Is

So for secondary current formula becomes

          Is = (Vp/Vs)×Ip =  (240/60) × 2

     Is = 4 × 2 = 8A

6 0
2 years ago
Identify the characteristics of protists. Check all that apply.
romanna [79]

Answer:

There are no examples

Explanation:

3 1
3 years ago
Read 2 more answers
A 2:2 kg toy train is con ned to roll along a straight, frictionless track parallel to the x-axis. The train starts at the origi
Liula [17]

Answer:

a) 10.51 J

b) 3.48 m/s

Explanation:

Given data :

mass of train ( M ) = 2.2 kg

Given initial velocity ( u ) = 1.6 m/s

<u>a) calculating work done by the force over the journey of the train</u>

F = mx + b  ------ ( 1 )

m = slope  = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m

x = distance travelled on the x axis by the train = 7.5 m

F = force experienced by the train = 2.8 N

x = 0

∴ b = 2.8

hence equation 1 can be written as

F = ( -0.373) x + 2.8   ----- ( 2 )

hence to determine the work done by the force

W   = \int\limits^7_0 { ( -0.373) x + 2.8  )} \, dx     Note:  the limits are actually 7.5 and 0

∴ W ( work done ) = -10.49 + 21 = 10.51 J

<u>b) calculate the speed of the train at the end of its journey</u>

we will apply the work energy theorem

W = 1/2 m*v^2  -  1/2 m*u^2

∴ V^2 = 2 / M ( W + 1/2 M*u^2 )  ( input values into equation )

 V^2 = 12.11

hence V = 3.48 m/s

6 0
3 years ago
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