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Ulleksa [173]
3 years ago
15

Consider a ball in projectile motion under gravitational force so that it is has motion in both the vertical and horizontal dire

ctions. The effects of air friction may be ignored. When the ball reaches the highest point in its trajectory, what can be said about the magnitudes of the ball's velocity and acceleration vectors? Select the correct answer
a. The horizontal components of both the velocity and acceleration are zero.
b. The magnitude of velocity is zero, but the acceleration is a constant
c. The magnitudes of both velocity and acceleration are zero
d. The magnitude of acceleration is zero but the ball has a positive velocity
e. The magnitude of velocity is at its minimum nonzero value, but the magnitude of acceleration is a constant
Physics
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

e.)The magnitude of velocity is at its minimum nonzero value, but the magnitude of acceleration is a constant

Explanation:

The speed of horizontal projectile is always constant for the duration of its flight. The reason behind this is that immediately the object is launched, the horizontal forces acting on the projectile is recorded as zero, and here the air resistance is negligible because because it is very minute therefore, horizontally projectile always travel at a constant speed.

At the same time, There is unbalanced forces directly acting on the ball and this will make the ball to accelerate into downward direction, Hence, the motion of vertical projectile is supported by the force of gravity. Since the vertical speed is not constant, acceleration is constant

Therefore, the magnitudes of the ball's is at the minimum nonzero value and velocity and acceleration vectors is constant.

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andrew-mc [135]
Impulse is just the product of mass and speed!

I = 1700 * 22.5  = 38,250 kg m/s

It does not have any special name for its units :(
3 0
3 years ago
The speed of an object undergoing constant acceleration increased from 8.0 meters per second to 16.0 meters per second in 10. Se
saw5 [17]

v₀ = initial speed of the object = 8 meter/second

v = final speed of the object = 16 meter/second

t = time taken to increase the speed = 10 seconds

d = distance traveled by the object in the given time duration = ?

using the kinematics equation

d = (v + v₀) t/2

inserting the above values in the above equation

d = (16 + 8) (10)/2

d = 120 meter


6 0
3 years ago
A car is up on a hydraulic lift at a garage. The wheels are free to rotate, and the drive wheels are rotating with a constant an
masya89 [10]

Answer:

Explanation:

Given

Wheels are rotating with constant angular velocity let say \omega

Presence of constant angular velocity show that there is no angular acceleration thus there is no tangential acceleration.

But any particle on the rim will experience a constant acceleration towards center called centripetal acceleration.

(a) yes, there will be tangential velocity which is given by

v=r\cdot \omega

where r=radial distance from center

(b)tangential acceleration

there would be no tangential acceleration as velocity is constant

(c)centripetal acceleration

Yes, there will be centripetal acceleration given by

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7 0
3 years ago
A 20 kg shopping cart moving at a velocity of 0.5 m/s collides with a store wall and
MAXImum [283]

Answer:

<h2>10 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 20 × 0.5

We have the final answer as

<h3>10 kg.m/s</h3>

Hope this helps you

7 0
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Applications of pressure
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