We are aware that weight is the product of applied gravitational force and mass. W = MG thus, where W represents the weight, M the mass, and G the gravitational force. As a result, it might also mean that "an object's weight is directly proportionate to its mass."
<h3>What is mass?</h3>
- Mass is a physical body's total amount of matter.
- It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force.
- The strength of an object's gravitational pull to other bodies is also influenced by its mass.
- The kilogram is the primary mass unit in the SI (kg).
- Even though weight is frequently measured using a spring scale rather than a balancing scale and directly compared with known masses, mass is not the same as weight in physics.
<h3>What is weight?</h3>
- The force exerted on an object by gravity is known as the weight of the object in science and engineering.
- Weight is sometimes described as a vector quantity, or the gravitational force exerted on the object, in some common textbooks.
- Others define weight as a scalar quantity, the gravitational force's strength.
- Others define it as the strength of the force applied to a body as a result of systems designed to resist the effects of gravity; the weight is the amount that is determined, for instance, by a spring scale.
Learn more about mass here:
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Answer:
Density is defined as mass per unit volume. its SI unit is: kg/m³
Explanation:
The solution for this problem is:
Let u denote speed.
Equating momentum before and after collision:
= 0.060 * 40 = (1.5 + 0.060) u
= 2.4 = 1.56 u
= 2.4 / 1.56 = 1.56 u / 1.56
= 1.6 m / s is the answer for this question. This is the speed after the collision.
Answer:
joules
joules
Explanation:
Let us convert the time in hours into seconds
Change in internal energy
where E is the internal energy in Joules
p is the power in watts
and t is the time in seconds
Joules
Amount of work done by the system
where P is the pressure and V is the volume
Substituting the given values in above equation, we get -
liter-atmospheres
Work done in Joules
Joules
Substituting the given values we get -
Thus
joules
joules
