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kipiarov [429]
3 years ago
12

Weightlessness is experienced by an astronaut in space. This means that the astronaut's muscles have to be stronger to move his

body or lift other objects.
True

False
Physics
2 answers:
just olya [345]3 years ago
4 0
The answer is false. The speed of the astronaut cancels out the force of gravity, causing a 'stationary freefall'. While under these effects, it is not required for an astronaut to 'strengthen' his body.
Svetradugi [14.3K]3 years ago
4 0

Answer:

False

Explanation:

Every thing on the surface of Earth is at a state of rest i.e., it has a constant force of gravity acting on it which keeps things planted on the ground. Let us take an example of an elevator. When we are going down we experience a little bit of weightlessness. Now, imagine an elevator going at a faster rate down our bodies will feel complete weightlessness. This is the same phenomenon experienced by the astronauts in low Earth orbit.

So, everything experiences weightlessness so the astronauts need not apply much force to move or lift objects.

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As a bullet shot vertically upward rises, the kinetic energy of the bullet
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The kenitc energy of the bullet lowers as it keeps going up.

Because gravity is pushing the bullet down as the bullet goes up.

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3 0
2 years ago
The symbol used for magnetic field is:
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5 0
3 years ago
A thin Nichrome wire connected to an ammeter surrounds a region of time-varying magnetic flux, and the ammeter reads 13 amperes.
Semenov [28]

Answer:

The current would be same in both situation.

Explanation:

Given that,

Current I = 13 A

Number of turns = 23

We need to calculate the induced emf

Using formula of induced emf is

\epsilon=NA\dfrac{dB}{dt}

For N = 1

\epsilon=A\dfrac{dB}{dt}

We need to calculate the current

Using formula of current

i=\dfrac{\epsilon}{R}

Put the value of emf

i=\dfrac{A\dfrac{dB}{dt}}{R}

Now, if the number of turn is 22 , then induced emf would be

\epsilon'=NA\dfrac{dB}{dt}

Then the current would be

i'=\dfrac{\epsilon'}{NR}

i'=\dfrac{NA\dfrac{dB}{dt}}{NR}

i'=\dfrac{A\dfrac{dB}{dt}}{R}

i'=i

Hence, The current would be same in both situation.

4 0
3 years ago
A speeding car traveling at 24.8 m/s passes a police car that is at rest. The police car begins its pursuit at the instant the s
marusya05 [52]

Answer:

the acceleration required is 1.37m/s^2

Explanation:

The car is having a constant velocity movement, so if we calculate the time to reach 897m, we can use it to find the acceleration the policeman need to apply to reach the car.

x=v*t\\t=\frac{x}{v}\\t=\frac{897m}{24.8m/s}\\t=36.17s

the policeman is traveling with a constant acceleration starting from rest so:

x=\frac{1}{2}*a*t^2\\\\a=\frac{2*x}{t^2}\\\\a=1.37 m/s2

7 0
3 years ago
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