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kipiarov [429]
4 years ago
12

Weightlessness is experienced by an astronaut in space. This means that the astronaut's muscles have to be stronger to move his

body or lift other objects.
True

False
Physics
2 answers:
just olya [345]4 years ago
4 0
The answer is false. The speed of the astronaut cancels out the force of gravity, causing a 'stationary freefall'. While under these effects, it is not required for an astronaut to 'strengthen' his body.
Svetradugi [14.3K]4 years ago
4 0

Answer:

False

Explanation:

Every thing on the surface of Earth is at a state of rest i.e., it has a constant force of gravity acting on it which keeps things planted on the ground. Let us take an example of an elevator. When we are going down we experience a little bit of weightlessness. Now, imagine an elevator going at a faster rate down our bodies will feel complete weightlessness. This is the same phenomenon experienced by the astronauts in low Earth orbit.

So, everything experiences weightlessness so the astronauts need not apply much force to move or lift objects.

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3 years ago
So what is 27+22? Is it <br> A 8338<br> B 8282<br> C 8228<br> D 8234
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Answer:

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6 0
3 years ago
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Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are
Vikentia [17]

Answer:

Speed of faster train equals 29 mph

Explanation:

Let the speed of slower train be 'x' miles per hour and the speed of faster train be 'y' miles per hour.

Distance that slower train covers in 2 hours=2\times x miles

Distance that faster train covers in 2 hours=2\times y miles

Since they move at right angles the distance between them can be found by Pythagoras formula as

d^{2}=(2x)^{2}+(2y)^{2}\\\\d^{2}=4(x^{2}+y^{2})\\(70.46)^{2}=4(x^{2}+y^{2})\\\\\therefore (x^{2}+y^{2})=\frac{(70.46)^{2}}{4}\\\\(x^{2}+y^{2})=\frac{4964.6}{4}\\\\(x^{2}+y^{2})=1241.15

It is given that y=x+9

Using this in the above equation we get

(x^{2}+y^{2})=1241.15\\\\x^{2}+(x+8)^{2}=1241.15\\2x^{2}+16x+64=1241.15\\2x^{2}+16x-1177.15=0

This is a quadratic equation in 'x'

Comparing with standard quadratic equation ax^{2}+bx+c we get value of x as

(x^{2}+y^{2})=1241.15\\\\x^{2}+(x+8)^{2}=1241.15\\2x^{2}+16x+64=1241.15\\2x^{2}+16x-1177.15=0\\\\x=\frac{-16\pm \sqrt{(16)^{2}-4\times 2\times -1177.15}}{2\times 2}\\\\x=\frac{-16\pm 98.35}{4}\\\\x=20.58mph(\because speed\neq

Thus speed of faster train = 28.58 mph

Speed of faster train = 19 mph

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