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kipiarov [429]
4 years ago
12

Weightlessness is experienced by an astronaut in space. This means that the astronaut's muscles have to be stronger to move his

body or lift other objects.
True

False
Physics
2 answers:
just olya [345]4 years ago
4 0
The answer is false. The speed of the astronaut cancels out the force of gravity, causing a 'stationary freefall'. While under these effects, it is not required for an astronaut to 'strengthen' his body.
Svetradugi [14.3K]4 years ago
4 0

Answer:

False

Explanation:

Every thing on the surface of Earth is at a state of rest i.e., it has a constant force of gravity acting on it which keeps things planted on the ground. Let us take an example of an elevator. When we are going down we experience a little bit of weightlessness. Now, imagine an elevator going at a faster rate down our bodies will feel complete weightlessness. This is the same phenomenon experienced by the astronauts in low Earth orbit.

So, everything experiences weightlessness so the astronauts need not apply much force to move or lift objects.

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Symbion pandora has a symbiotic relationship with the Norway lobster. True False
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5 0
4 years ago
2. While standing near a bus stop, a student hears a distant horn beeping. The frequency emitted by the horn is 440 Hz. The bus
jarptica [38.1K]

Given Information:

Frequency of horn = f₀ = 440 Hz

Speed of sound = v = 330 m/s

Speed of bus = v₀ = 20 m/s

Answer:

Case 1. When the bus is crossing the student = 440 Hz

Case 2. When the bus is approaching the student = 414.9 Hz

Case 3. When the bus is moving away from the student = 468.4 Hz

Explanation:

There are 3 cases in this scenario:

Case 1. When the bus is crossing the student

Case 2. When the bus is approaching the student

Case 3. When the bus is moving away from the student

Let us explore each case:

Case 1. When the bus is crossing the student:

Student will hear the same frequency emitted by the horn that is 440 Hz.

f = 440 Hz

Case 2. When the bus is approaching the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330+20 )

f = 440 ( 330/ 350 )

f = 440 ( 0.943 )

f = 414.9 Hz

Case 3. When the bus is moving away from the student

f = f₀ ( v / v+v₀ )

f = 440 ( 330/ 330-20 )

f = 440 ( 330/ 310 )

f = 440 ( 1.0645 )

f = 468.4 Hz

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3 years ago
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The answer is A = 20 units
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