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Marrrta [24]
3 years ago
12

What determines how soon one action potential can follow another?

Physics
1 answer:
belka [17]3 years ago
5 0
It is through biopsychological feedback. 

A class of chemical called a neurotransmitter is important in the transmission of nerve impulses. Neurotransmitters are packaged by the cell into small, membrane-bound sacs called vesicles. Upon receiving a chemical signal, the vesicles move toward the cell membrane and fuse with it, releasing the enclosed neurotransmitters from the terminal end of the nerve cell. 
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Brian is given an unknown element that is bright when sunlight hits it. He has a hammer and an electrical source. If he attached
ikadub [295]
Metalloids are between metals and non-metals. Metals conduct electricity while Non-metals do not. Since metalloids are somewhere in between, then the substance may conduct some electricity. Hope it helps.
4 0
3 years ago
Read 2 more answers
Avogadro's law states that: A. The volume of a fixed amount of gas is directly proportional to its temperature in Kelvin at cons
Travka [436]

Answer:

C. Equal amounts of gases occupy the same volume at constant temperature and pressure.

Explanation:

As we know by ideal gas law that

PV = nRT

now here we have

V = \frac{RT}{P} n

so as per Avagadro law if the temperature and pressure of the gas is constant then volume of the gas is directly proportional to the number of moles of the gas.

so correct answer will be given as

C. Equal amounts of gases occupy the same volume at constant temperature and pressure.

3 0
3 years ago
A charged particle is observed traveling in a circular path in a uniform magnetic field. If the particle had been traveling four
8090 [49]

Answer:

The new radius of the trajectory of the particle is four times the previous radius

Explanation:

In order to know what is the radius of the trajectory of the charged particle, if its speed is four times as fast, you take into account the following formula, which describes the radius of a charged particle in a magnetic field:

r=\frac{mv}{qB}          (1)

If the speed of the particle is for time as fast, that is, v' = 4v, you obtain, in the equation (1):

r'=\frac{mv'}{qB}=\frac{m(4v)}{qB}=4\frac{mv}{qB}=4r

The new radius of the trajectory of the particle is four times the previous radius

8 0
3 years ago
A parallel beam of light from a laser with a wavelength 450 nm, falls on a grating whose slits are 1.28 x 10^-4 cm apart. How fa
Katena32 [7]

Answer:

Y_1 = 1.195 m = 119.5 cm

Explanation:

For nth order bright fringe, the distance from the center of the pattern is given by :-

Y_n = \frac{n\lambda D}{d}.

Where,

n = order of nth  bright fringe. = 1

\lambda = wavelength of  given light  =  450 nm = 450*10-{9} m

D = distance between the screen and slits. =  3.4 m

and d = separation between the slits. = 1.28 *10^{-4} cm =1.28 *10^{-6} m

Y_1 = \frac{(1 *450 *10{-9} *3.4)}{(1.28*10{-6})}

Y_1 = 1.195 m = 119.5 cm

7 0
3 years ago
Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at
sergiy2304 [10]

Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

6 0
3 years ago
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