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3 years ago

Which is true about the velocity of sound waves in solids compared to air

Physics

2 answers:

tankabanditka [31]3 years ago

4 0

C. Travels slower in solids because the particles are closer together.
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DiKsa [7]3 years ago

4 0

Answer: Third option; "travels slower in solids because particles are close together"

Explanation: While in the air the particles are very freely and the sound does not need to do a lot of work, in a dense material this is not the case. The particles are more close together, and this causes that in a fixed distance, the sound wave needs to move more particles in a solid than in the air. This makes the sound wave to travel slower when it is in a solid.

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A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap

viktelen [127]

Answer:

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

Explanation:

As we know that they are in series so the voltage across all three will be sum of all individual voltages

so it is given as

$V_r + V_L + V_c = V_{net}$

now we will have

$iR + L\frac{di}{dt} + \frac{q}{C} = 12 V$

now we have

$1\frac{d^2q}{dt^2} + (5 \times 10^3) \frac{dq}{dt} + \frac{q}{0.25 \times 10^{-6}} = 12$

So we will have

$q = 3\times 10^{-6} + c_1 e^{-4000 t} + c_2 e^{-1000 t}$

at t = 0 we have

q = 0

$0 = 3\times 10^{-6} + c_1 + c_2$

also we know that

at t = 0 i = 0

$0 = -4000 c_1 - 1000c_2$

$c_2 = -4c_1$

$c_1 = 1 \times 10^{-6}$

$c_2 = -4 \times 10^{-6}$

so we have

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

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3 years ago

In your own words, explain the effects of time dilation.

Natalka [10]

So we want to explain the effects of time dilation. In theory of relativity time dilation is the difference of elapsed time between two events when measured by two observers who are moving relatively to each other. A clock of an observer that is standing still in an inertial frame of reference is going to measure a different time of an event than the clock of an observer that is moving with some velocity with respect to the inertial reference frame that is not moving. In a nutshell, the moving clock is ticking slower than the clock that is standing still.

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3 years ago

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Usually, tall trees collapse in stroms?<br>

sergey [27]

Taller trees are more likely to fall during storms than short trees.

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To collect quantitative data, scientists use all of the following except

Sever21 [200]

"Quantitative" means "expressed in numbers". Quantitative data is information you collect by using measuring tools, and measuring things.