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Answer:
K = 109.1 N/m
Explanation:
From the question, the following parameters are given.
Extension e = 55 m
Force F = 6000N
According to Hooke's law,
F = Ke
Where K = spring constant.
Substitute F and e into the formula and make K the subject of formula.
6000 = K × 55
K = 6000/55
K = 109.1 N/m
Therefore, the spring constant of a bungee cord that stretches is 109.1 N/m
Sorry I didn't see this before...
Okay, I see two major problems with this student's experiment:
1) Nitric acid Won't Dissolve in Methane
Nitric acid is what's called a mineral acid. That means it is inorganic (it doesn't contain carbon) and dissolves in water.
Methane is an organic molecule (it contains carbon). It literally cannot dissolve nitric acid. Here's why:
For nitric acid (HNO3) to dissolve into a solvent, that solvent must be polar. It must have a charge to pull the positively charged Hydrogen off of the Oxygen. Methane has no charge, since its carbon and hydrogens have nearly perfect covalent bonds. Thus it cannot dissolve nitric acid. There will be no solution. That leads to the next problem:
2) He's Not actually Measuring a Solution
He's picking up the pH of the pure nitric acid. Since it didn't dissolve, what's left isn't a solution—it's like mixing oil and water. He has groups of methane and groups of nitric acid. Since methane is perfectly neutral (neither acid nor base), the electronic instrument is only picking up the extremely acidic nitric acid. There's no point to what he's doing.
Does that help?
Answer:
Work W=4.16 Btu
Heat transfer Q=14.56 Btu
Explanation:
To calculate the work W we will use the given pressure p=30 psia and volume V₁=0.75 ft³ V₂=2.V₁
![W=p.(V_{2}-V_{1} )\\W=30psia.(1.5ft^{3}-0.175ft^{3} ).\frac{144in^{2} }{1ft^{2} } .\frac{1Btu}{778lbf.ft}\\ W=4.16Btu](https://tex.z-dn.net/?f=W%3Dp.%28V_%7B2%7D-V_%7B1%7D%20%29%5C%5CW%3D30psia.%281.5ft%5E%7B3%7D-0.175ft%5E%7B3%7D%20%29.%5Cfrac%7B144in%5E%7B2%7D%20%7D%7B1ft%5E%7B2%7D%20%7D%20.%5Cfrac%7B1Btu%7D%7B778lbf.ft%7D%5C%5C%20W%3D4.16Btu)
Now for heat transfer
![Q=W+m.(u_{2}-u_{1} )\\Q=W+\frac{m.R.(T_{2}- T_{1})}{k-1}\\](https://tex.z-dn.net/?f=Q%3DW%2Bm.%28u_%7B2%7D-u_%7B1%7D%20%29%5C%5CQ%3DW%2B%5Cfrac%7Bm.R.%28T_%7B2%7D-%20T_%7B1%7D%29%7D%7Bk-1%7D%5C%5C)
The last equation we will rewrite using ideal gas law to calculate heat transfer
![Q=W+\frac{p(V_{2}-V_{1} )}{k-1}\\ As\\W=p(V_{2}-V_{1} )\\So\\Q=W+\frac{W}{k-1} \\Q=4.16Btu+\frac{4.16Btu}{1.4-1} \\Q=14.56Btu](https://tex.z-dn.net/?f=Q%3DW%2B%5Cfrac%7Bp%28V_%7B2%7D-V_%7B1%7D%20%29%7D%7Bk-1%7D%5C%5C%20As%5C%5CW%3Dp%28V_%7B2%7D-V_%7B1%7D%20%29%5C%5CSo%5C%5CQ%3DW%2B%5Cfrac%7BW%7D%7Bk-1%7D%20%5C%5CQ%3D4.16Btu%2B%5Cfrac%7B4.16Btu%7D%7B1.4-1%7D%20%5C%5CQ%3D14.56Btu)
The Station, As it is a stationery object therefore making it easier to get a relative speed estimate. (Sorry for the pun as well)