Answer:
Change in area=24
-48
Step-by-step explanation:
Let s will be the side of square and r will be the radius of circle.
Then two given conditions are
1)dr/dt=2 m/s
2)ds/dt=1 m/s
Area enclosed=(Area of square)-(Area of circle)
Area of square=
Area of circle=
Area enclosed=
dA/dt=2
r(dr/dt)-2s(ds/dt)
At s=24,and r=6
dA/dt=2(
)(6)(2)-2(24)(1)
Change in area=24
-48
Hello!
To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile.
33 - 25 = 8
The interquartile range is 8. Hope I helped! :3
X² - 6x - 9 = 0
x² - 3x - 3x - 9 = 0
x (x-3) -3(x + 3) = 0
(x - 3)² = 0
In short, Your Answer would be Option A
Hope this helps!
Answer:
D. A rotation 270º counterclockwise about the origin
Step-by-step explanation:
Answer: option c or 3 because you gotta take out the 6 so u do -6 which left is negative and right is positive and then get rid of the +2 exponent so up is positive and down is negative so you move -2 which is down.
Step-by-step explanation: