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Jobisdone [24]
3 years ago
13

Hydrogen can reduce copper oxide but not aluminium oxide explain​

Chemistry
2 answers:
Kitty [74]3 years ago
7 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  ━━━━━━━━━━━━━━ ★✼☆。

- It's all to do with the reactivity series

Copper is below hydrogen in the reactivity series

Thus it can reduce copper by taking the oxygen from it

However, aluminium is above hydrogen in the reactivity series so it wouldn't be possible.

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

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Llana [10]3 years ago
3 0

Answer: as copper has lower electrode potential value than hydrogen, it could be reduced by hydrogen.

Explanation: hydrogen has zero reduction potential while Cu has +0.34V and Al has -1.66 V .

SO in electrochemical series who has most negative or less reduction potential value tends to be a good reducing agent than the other.

Hope it helps...

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7. Complete the concept map below.
Ilya [14]

Drainage that is not handled properly can cause an increase in erosion, changes in stormwater runoff, flooding, and damage to water quality.

<h3>Natural Disaster?</h3>
  • Large-scale geological or meteorological phenomena that have the potential to cause loss of life or property are considered natural disasters.
  • Tornadoes and severe storms are examples of these catastrophes. Tropical Storms and Hurricanes. Floods.
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To learn more  about Natural Disaster refer to:

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4 0
1 year ago
g On the basis of their respective pKa values, determine which is the stronger acid, acetic acid (pKa 5 4.7) or benzoic acid (ma
ozzi

Answer:

Benzoic acid is the stronger acid

Explanation:

Weak acids do not dissociate completely in the solution. They exists in equilibrium with their respective ions in the solution.

The extent of dissociation of the acid furnising hydrogen ions can be determined by using dissociation constant of acid (K_a).

Thus for a weak acid, HA

HA \rightleftharpoons A^- + H^+

The K_a is:

K_a= \frac{[A^-][H^+]}{[HA]}

The more the K_a, the more the acid dissociates, the more the stronger is the acid.

Also,

pK_a is defined as the negative logarithm of K_a.

So, more the pK_a, less is the K_a and vice versa

All can be summed up as:

The less the value of pK_a, the more the  K_a is and the more the acid dissociates and the more the stronger is the acid.

Given,

pK_a of acetic acid = 54.7

pK_a of benzoic acid = 54.2

pK_a of benzoic acid < pK_a of acetic acid

So, benzoic acid is the stronger acid.

5 0
3 years ago
Chlorine is more reactive than nitrogen why​
OLga [1]

But nitrogen is inert at room temperature whereas chlorine is highly reactive, the reason is: Nitrogen exists as N triple bond N at room temperature while chlorine exists as Cl single bond Cl at room temperature. Since the bond dissociation energy of triple bond is larger than that of single bond.

4 0
3 years ago
What are the benefits of scientists using the metric system worldwide?select all that apply
denis-greek [22]

There are several scales to determine the weight of material. The chose of the weight scale depends upon the size of the material. Like if we have to measure the molecular or atomic weight of  a molecule or atom we use gm. Like that for the bigger molecules like proteins the weight of the molecule is expressed by different scale due to its big size. Like that for big material like iron rods etc we generally use kilograms or ton. There are two types of measuring units one is C.G.S. and another is S.I. The S.I. units are more acceptable worldwide than that the C.G.S. units as the digit comes in SI units are easily handable than that of CGS.

Thus metric is used to determine a large weight of compounds which is a SI unit and handable.    

4 0
3 years ago
The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea
Mariana [72]

Answer:

\frac{1}{8}  

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}  

We can construct a table.

<u>No of half-lives</u>  <u>Fraction remaining</u>

            1                       \frac{1}{2}  

            2                      \frac{1}{4}  

            3                      \frac{1}{8}  

The general formula is

\text{Fraction remaining} = \frac{1}{2^{n}}

where <em>n</em> = the number of half-lives.

Thus, \frac{1}{8} of the original carbon remains after 17 190 y.

8 0
3 years ago
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