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Jobisdone [24]
3 years ago
13

Hydrogen can reduce copper oxide but not aluminium oxide explain​

Chemistry
2 answers:
Kitty [74]3 years ago
7 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  ━━━━━━━━━━━━━━ ★✼☆。

- It's all to do with the reactivity series

Copper is below hydrogen in the reactivity series

Thus it can reduce copper by taking the oxygen from it

However, aluminium is above hydrogen in the reactivity series so it wouldn't be possible.

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

。☆✼★ ━━━━━━━━━━━━━━  ☾  ━━━━━━━━━━━━━━ ★✼☆。

Llana [10]3 years ago
3 0

Answer: as copper has lower electrode potential value than hydrogen, it could be reduced by hydrogen.

Explanation: hydrogen has zero reduction potential while Cu has +0.34V and Al has -1.66 V .

SO in electrochemical series who has most negative or less reduction potential value tends to be a good reducing agent than the other.

Hope it helps...

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An unknown element, X, reacts with oxygen to form two oxides with the general formula X_2O_3 and X_2O_5. The pure element is str
Gelneren [198K]

Answer:

The unknown element is Sb

Explanation:

The first thing we must note is that the unknown element must be a member of group 15 in the periodic table. This is clear from the fact that the two oxides formed are X2O3 and X2O5. This implies that the unknown element X must have a valency of 3 or 5. This corresponds to our knowledge that the outermost electron configuration of group 15 elements is ns2np3. Hence, group fifteen elements can have a valency of 3 or 5.

The electronic configuration of antimony is; [Kr]4d10 5s2 5p3. This implies that the atom is paramagnetic since there are three unpaired 5p electrons. The oxides of antimony are known to be amphoteric. An ampohoteric oxide reacts with both acid and base, hence the answer.

6 0
3 years ago
A solution has a pH of 12. This solution is:
kolezko [41]

Answer:

basic

Explanation:

pH 7: neutral

12>7

so it is basic

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3 0
3 years ago
What is the effect of adding heat to a gas at constant pressure?
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8 0
3 years ago
For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 57
Lelu [443]
The %  yield  if  500 g of  sulfur trioxide  reacted  with  excess  water to   produce  575 g  of  sulfuric  acid is calculated using  the  below  formula


%  yield = actual  yield/ theoretical  yield  x100

actual  yield =575 grams
to  calculate  theoretical  yield
find the  moles  of SO3   used =mass/molar  mass
=  500g/   80 g/mol =6.25  moles

SO3+H2O=H2SO4
by   use of  mole ratio  of SO3  :  H2SO4 which  is 1:1  the moles of H2SO4  is  also=  6.25  moles

the theoretical  yield of H2SO4 is therefore =  moles /molar  mass
=  6.25  x98=  612.5 grams

%yield  is therefore= 575 g/612 g   x100=  93.9  %

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