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lilavasa [31]
3 years ago
5

Based on this information which of the following conclusions can be drawn about the growth rate of grass? hurry

Chemistry
1 answer:
Vlad [161]3 years ago
7 0
A is the answer I know bc I take biology
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Consider the reaction Cl 2(g) + Br 2(g) <=> 2 BrCl(g), which is endothermic as written. What would be the effect on the eq
Elodia [21]

According to Le Châtelier's principle, an increase in temperature favors the endothermic process. Since the reaction, which proceeds towards bromine chloride, is endothermic, the reaction would shift right, making more products.

3 0
3 years ago
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How many liters of 0.37 M solution can be made with 29.53 grams of lithium fluoride.<br> (LiF)?
dsp73

Answer:

V = 3.1 L      

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L         (M = mol/L)

4 0
3 years ago
A drink is made up mostly of water. A small amount of sweet powder is stirred in using a spoon. The power in this solution is th
Helen [10]
Well the solvent is the liquid in a solution so your answer would be Solute, D. That is the one that would represent the sugar crystals being evenly mixed into a solution.
6 0
3 years ago
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Percent Composition and Determining Empirical And Molecular Formulas
raketka [301]

Answer:

% comp. H = 2.8%, % comp. Cl = 97.2%

Explanation:

HCl mass = mass of H + mass of Cl

HCL mass = 1.00794 + 35.453 = 36.46094

% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)

% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)

3 0
2 years ago
You find a compound composed only of element X and chlorine and you know that the compound is 13.10% X by mass. Each molecule of
8_murik_8 [283]

Answer:

Explanation:

So, the formula for the compound should be:

XCl_{6}

Now we assume that we have 1 mol of substance, so we can make calculations to know the molar mass of element X, as follows:

M_{Cl}=35.45g/mol\\

So we have that 6 moles weight 212.7g, and we can make a rule of three to know the weight of compound X:

212.7g\rightarrow 86.9\%\\x\rightarrow 13.1\%\\\\x=\frac{212.7g*13.1}{86.9} =32.06g

As we used 1 mol, we know that the molar mass is 32.06g/mol

So the element has a molar mass of 32.06 g/mol and an oxidation state of +6, with this information, we can assure that the element X is sulfur, so the compound is SCl_{6}

8 0
3 years ago
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