Answer:
ELASTIC collision
kinetic energy is conservate
Explanation:
As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.
As the floor does not move the conservation of the moment
po = pf
-mv1 = m v2
- v1 = v2
So the speed with which it descends is equal to the speed with which it rises
Therefore the kinetic energy of the ball before and after the collision is the same
<u>Hello and Good Morning/Afternoon</u>:
<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>
<u>To balance this equation</u>:
⇒ must ensure that there is an equal number of elements on both sides of the equation at all times
<u>Let's start balancing:</u>
- On the left side of the equation, there are 2 carbon molecule
⇒ but only so far one on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + __ H₂O</em>
- On the left side of the equation, there are 6 hydrogen molecules
⇒ but only so far two on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + 3H₂O</em>
- On the right side of the equation, there are 7 oxygen molecules
⇒ but only so far three on the left side
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<u>Let's check and make sure we got the answer:</u>
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<em> 2 Carbon ⇔ 2 Carbon</em>
<em> 6 Hydrogen ⇔ 6 Hydrogen</em>
<em> 7 Oxygen ⇔ 7 oxygen</em>
<u>Thefore the coefficients in order are</u>:
⇒ 1, 3, 2, 3
<u>Answer: 1,3,2,3</u>
Hope that helps!
#LearnwithBrainly<em> </em>
In an inelastic collision, only momentum is conserved, while energy is not conserved.
1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:

where
m=0.1 kg is the mass of the nail
M=10 kg is the mass of the block of wood
Rearranging the formula, we find

, the velocity of the nail and the block after the collision:

2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:

Rearranging the formula, we can find

, the velocity of the nail before the collision:
Finding acceleration= final velocity-initial velocity/ time taken (or A= V-U/T)
Final speed= 2m
Initial speed= 0m
Time taken= 2 seconds
2-0/2 so it’ll be 1m/s
2-0=0
2/2=