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3 years ago

ATTENTION! I NEED THIS DONE ASAP NO LINKS !!! THIS IS A SCIENCE QUESTION

Physics

1 answer:

nata0808 [166]3 years ago

4 0

Answer:

Science seeks to broaden our knowledge base, while engineering designs solutions and problems.

Explanation:

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Wich of the following is NOT an example of accelerated motion?

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B is the answer for your question the answer is b an elevator slowing down

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3 years ago

Read 2 more answers

Starting from rest, a car takes 2.4s to travel 15m. Assuming a constant acceleration, how long will it take the car to travel th

Alborosie

Answer:

T = 2.4 + 2.4 = 4.8 [s]

Explanation:

In order to solve this problem, we must use the following kinematics equation and calculate the acceleration value.

$x=x_{o} +v_{o}*t+(\frac{1}{2})*a*t^{2}$

Vo = inital velocity = 0

x - xo = 15 [m]

t = time = 2.4 [s]

15 = 0.5*a*(2.4)^2

a = 5.208 [m/s^2]

We can use the same equation to find the time.

30 = 15 + 0.5*(5.208)*t^2

t = 2.4 [s]

T = 2.4 + 2.4 = 4.8 [s]

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3 years ago

⚠HI YOU GUYS HELLLP BRAINLIEST AND 100 PIONTS⚠ Use THE MAP

Setler [38]

Answer:

5.A mid-ocean ridge or mid-oceanic ridge is an underwater mountain range, formed by plate tectonics. This uplifting of the ocean floor occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary.

6.The Nazca plate is an oceanic plate, while the South American plate is continental. The fast moving Nazca plate is moving east towards the South American plate at a downward angle and converging. This process is called subduction, resulting in frequent earthquakes & production of the Andes Mountains.

7.The Nazca plate forms the southeastern part of the Pacific plate. The Nazca and the Pacific plate share both divergent and transform type of plate boundary. The Pacific and the Nazca plate are separating at an increasing rate of about 122-142mm/year.

8.Convection currents in the mantle and in the ocean are similar because they both are responsible for the shaping the Earth's surface. Two forces are behind the movement of Earth's huge land masses. Due to combined action of convection currents and gravity, Earth's plates are in constant motion.

Explanation:

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3 years ago

You ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. the reading on the

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The reading on the scale is greater than your actual weight.

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3 years ago

A section of a parallel-plate air waveguide with a plate separation of 7.11 mm is constructed to be used at 15 GHz as an evanesc

adell [148]

Answer:

the required minimum length of the attenuator is 3.71 cm

Explanation:

Given the data in the question;

we know that;

$f_{c_1$ = c / 2a

where f is frequency, c is the speed of light in air and a is the plate separation distance.

we know that speed of light c = 3 × 10⁸ m/s = 3 × 10¹⁰ cm/s

plate separation distance a = 7.11 mm = 0.0711 cm

so we substitute

$f_{c_1$ = 3 × 10¹⁰ / 2( 0.0711 )

$f_{c_1$ = 3 × 10¹⁰ cm/s / 0.1422 cm

$f_{c_1$ = 21.1 GHz which is larger than 15 GHz { TEM mode is only propagated along the wavelength }

Now, we determine the minimum wavelength required

Each non propagating mode is attenuated by at least 100 dB at 15 GHz

Attenuation constant TE₁ and TM₁ expression is;

∝₁ = 2πf/c × √( ( $f_{c_1$ / f)² - 1 )

so we substitute

∝₁ = ((2π × 15)/3 × 10⁸ m/s) × √( (21.1 / 15)² - 1 )

∝₁ = 3.1079 × 10⁻⁷

∝₁ = 310.79 np/m

Now, To find the minimum wavelength, lets consider the design constraint;

20log₁₀ $e^{-\alpha _1l_{min$ = -100dB

we substitute

20log₁₀ $e^{-(310.7np/m)l_{min$ = -100dB

$l_{min$ = 3.71 cm

Therefore, the required minimum length of the attenuator is 3.71 cm

6 0

3 years ago