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zmey [24]
3 years ago
8

Two astronauts of identical mass are connected by a taut cable of negligible mass, as shown in the figure above, and are initial

ly at rest with respect to a nearby space station. Astronaut Y pulls on the cable toward herself with considerable force. Which of the following describes the direction of the velocity of the center of mass of the two astronauts after Astronaut Y pulls on the cable?
Physics
1 answer:
PolarNik [594]3 years ago
5 0

Answer:

The right answer is "The center of mass doesn't move".

Explanation:

  • It generates a voltage throughout the cable while the astronaut falls on either the wire. At other ends of the spectrum or cable, the tension will be similar. As such, with both astronauts, there would be the same energy, although throughout the opposite way.
  • Thus, the net force seems to be essentially negative on the machine. And therefore the mass center stays stationary.
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A 750-kg automobile is moving at 26.2 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car
Kisachek [45]

To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore

Potential Energy can be defined as,

PE = mgh

Kinetic Energy can be defined as,

K= \frac{1}{2} mv^2

Now for Conservation of Energy,

KE_i+PE_i = PE_f

\frac{1}{2}mv_i^2+mgh_1 = mgh_2

\frac{1}{2} (750kg) (26.2m/s)^2 + (750)(9.8)(5) = (750)(9.8)h_2

h_2 = 40.0224m

Therefore the highets position the car reaches above the bottom of the hill is 40.02m

6 0
4 years ago
At the same instant that a 0.50 kg ball is dropped from 25 m above Earth, a second ball, with a mass of .25 kg, is thrown straig
Anettt [7]

Answer:

A. 7.1m

B. 3.55m/s

C. 1.775m/s^2

Explanation:

First step is to identify given parameters;

Ball 1: m₁ = 0.5kg, u (initial velocity) =0, t = 2seconds

Ball 2: m₂ = 0.25kg, u = 15m/s, t = 2seconds

<u>Second step:</u> we determine the y-coordinate of ball 1 after 2 seconds, using the equation of motion under gravity as shown below;  

y = ut - \frac{gt^2}{2}

y_{1} = 0 X 2 - \frac{9.8 X2^2}{2}

y_{1} = -19.6m

Recall, that the ball was thrown from a height of 25m, total y-coordinate of ball 1 after 2 seconds becomes 25m +(-19.6m)

[tex]y_{1}  = 5.4m[/tex]

<u>Third step</u>: we determine the y-coordinate of ball 2 after 2 seconds

y_{2} = 15 X 2 - \frac{9.8 X2^2}{2}

y_{2} = 10.4m

<u>Fourth step: </u>we determine the y-component of the center mass of the two balls

y = \frac{m_{1}y_{1} +m_{2}y_{2}}{m_{1} +m_{2} }

y = \frac{(0.5)X(5.4) +(0.25) X (10.4)}{(0.5 +0.25) }

y = 7.1m

<u>Fifth step:</u> we solve B part of the question; velocity of the center mass of the two balls

Velocity = \frac{distance of center mass of the two balls (y)}{time}

velocity = \frac{7.1 m}{2 s}

velocity = 3.55m/s

<u>Sixth step:</u> we solve C part of the question; acceleration of the center mass of the two balls

acceleration = \frac{velocity}{time}

acceleration = \frac{3.55}{2}

acceleration = 1.775 m/s^2

7 0
3 years ago
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collisi
Komok [63]

Answer:

D. 200 kgm/s

Explanation:

Momentum is conserved.

Initial momentum = final momentum

(50 kg) (4 m/s) + (30 kg) (0 m/s) = final momentum

200 kgm/s = final momentum

8 0
3 years ago
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The landing gear of an airplane can be idealized as the spring-mass-damper system shown in fig. 3.52. if the runway surface is d
Serhud [2]
The land of airplane gear of an airplane can be idealized as the spring-mass-damper system shown in fig. 3.52. if the runway surface is described
5 0
3 years ago
A generator makes 3.45 kilojoules (kJ) of energy during each minute of
erastovalidia [21]
The total energy produced by the generator is 3.45 kJ. Of this energy, 2.23 kJ are lost because friction and electrical resistance, so this amount of energy is converted into thermal energy. This means that the rest of the energy is available as electric energy, and it is equal to:
E=3.45 kJ-2.23 kJ=1.22 kJ
6 0
4 years ago
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