1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zmey [24]
3 years ago
8

Two astronauts of identical mass are connected by a taut cable of negligible mass, as shown in the figure above, and are initial

ly at rest with respect to a nearby space station. Astronaut Y pulls on the cable toward herself with considerable force. Which of the following describes the direction of the velocity of the center of mass of the two astronauts after Astronaut Y pulls on the cable?
Physics
1 answer:
PolarNik [594]3 years ago
5 0

Answer:

The right answer is "The center of mass doesn't move".

Explanation:

  • It generates a voltage throughout the cable while the astronaut falls on either the wire. At other ends of the spectrum or cable, the tension will be similar. As such, with both astronauts, there would be the same energy, although throughout the opposite way.
  • Thus, the net force seems to be essentially negative on the machine. And therefore the mass center stays stationary.
You might be interested in
Which of the following is a purpose of rules in sports and games? (5 points)
ValentinkaMS [17]

Answer:

To keep everyone safe

Explanation:

Without rules people could get hurt

4 0
3 years ago
a crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one
prohojiy [21]

The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be 37^oC is 367.42 Hz.

A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.

The fundamental frequency in the tube is given by

f=\frac{v_T}{4L}

where, v_T=v\sqrt{\frac{T}{273} }

Since, T=37+273 K = 310 K

v = 331 m/s

\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s

Using this, we get:

f=\frac{352.72}{4(0.240)} \\f=367.42 \ Hz

Hence, the fundamental frequency is 367.42 Hz.

To learn more about Attention here:

brainly.com/question/14673613

#SPJ4

7 0
2 years ago
An electron moves with a speed of 5.0 x 10^4m/s
Firlakuza [10]

Answer:

F=1.6\times 10^{-15}\ N

Explanation:

Given that,

Speed of the electron, v=5\times 10^4\ m/s

Magnetic field, B = 0.20 T

We need to find the magnitude of magnetic force on the electron. The formula for the magnetic force is given by :

F=qvB\ sin\theta

Here, \theta=90^{\circ}

F=qvB, q is the charge on electron

F=1.6\times 10^{-19}\times 5\times 10^4\times 0.2

F=1.6\times 10^{-15}\ N

So, the magnitude of the magnetic force on the electron is 1.6\times 10^{-15}\ N. Hence, this is the required solution.

4 0
3 years ago
Someone plss asnwer i need help amswer only if u know it​
My name is Ann [436]

Answer:

going backwards message me if u have any problems

7 0
3 years ago
Read 2 more answers
A sled of mass 8 kg slides along the ice. It has an initial speed of 4 m/s but
marysya [2.9K]

As our story begins, the sled ... whose mass is 8 kg ...  is sliding along the ice at a speed of 4 m/s.

The sled's kinetic energy is (1/2 m v²) = (4 kg · 16 m²/s²) = 64 J .

After what seems like only the blink of an eye, the sled is no longer sliding.  It is stationary.  Motionless.  At Rest.  Just sitting there !  

Its speed has been reduced to zero and ... because kinetic energy is the energy of motion ... the sled's kinetic energy is now also zero.  Sixty-four Joules of energy have disappeared !

How can this be ? ! ? We know that energy is conserved.  It can never just appear out of nothing, and it can never just disappear into nothing.  If energy suddenly appears, it had to come from somewhere, and if energy suddenly disappears, it had to go somewhere.  So where did our 64 Joules of kinetic energy go ?

It went into the ice, THAT's where !  We can say that the sled did 64J of work, and melted a thin slick layer of water on the surface of the ice.  OR we can say that friction did NEGATIVE 64J of work on the sled, to cancel the 64J that it had originally, sap its kinetic energy, and bring it to rest.

I think <em>choice-B</em> was supposed to say "<em>B. -64J</em>", but somebody typed it sloppily and neglected to proofread it before posting.

6 0
3 years ago
Other questions:
  • In order to move a bag of dog food Across the 10 meter room you apply 20 newtons of force how much work was done
    11·1 answer
  • If a force of 3000 N is applied to a large rock, but the rock does not move, how much work is done on the rock?
    8·1 answer
  • Let the four horizontal compass directions north, east, south, and west be represented by units vectors n^, e^, s^, and w^, resp
    7·1 answer
  • If the cyclist has 2000 j of potential energy at point c how high is the hill
    14·1 answer
  • I need help wit this physics question.
    15·1 answer
  • What is the speed of a jet plane that flies 8100 km in 27 hours (in km/hr)
    12·1 answer
  • If a sled has at the top of 10 m hill had 1000 J of potential energy what would happen to the PE if the sled were to moved to a
    11·1 answer
  • When equipment or motors need to be operated momentarily for inching, what's the ideal circuit to use?
    6·1 answer
  • Summarize why you need a partner for the Unit 4 lab.<br> Your answer
    15·1 answer
  • What does black hole consists of? singularity?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!