All categories

3 years ago

Express 79 m in units of (a) centimeters

Physics

1 answer:

dem82 [27]3 years ago

8 0

Answer: a) 7,00 centimeters

(b) 259. 19 feet

(d) 0.049 miles

Explanation:

(a) We know that 1 meter = 100 centimeters

Therefore,

$79\ m= 7,900\text{ centimeters}$

(b)Since 1 meter = 3.28084 feet

Then, $79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}$

(c) Since, 1 feet = 12 inches.

$79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}$

(d) $\text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}$

$79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}$

You might be interested in

When the displacement of a mass on a spring is 12 a the half of the amplitude, what fraction of the mechanical energy is kinetic

Sveta_85 [38]

You know that when the displacement is equal to the amplitude (A), the velocity is zero, which implies that the kinetic energy (KE) is zeero, so the total mechanical energy (ME) is the potential energy (PE).

And you know that the potential energy, PE, is [ 1/2 ] k (x^2)

Then, use x = A, to calculate the PE in the point where ME = PE.

ME = PE = [1/2] k (A)^2.

At half of the amplitude, x = A/2 => PE = [ 1/2] k (A/2)^2

=> PE = [1/4] { [1/2]k(A)^2 } = .[1/4] ME

So, if PE is 1/4 of ME, KE is 3/4 of ME.

And the answer is 3/4

7 0

3 years ago

The direction of centripetal force is away from the axis of rotation.

Arada [10]

I’m pretty sure it’s true x

4 0

2 years ago

Read 2 more answers

A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the proces

snow_lady [41]

Answer:

The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds.

Initial velocity = 33 m/s

Final velocity = 0 m/s

Average velocity = (33 + 0) / 2 m/s = 16.5 m/s

Explanation:

First, how long does it take the truck to come to a complete stop?

( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds

Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.

4 0

2 years ago

Hello I need some help.Two guys enetr in a room,a guy come from outside(there is cold)and another guy come from a room(there is

slavikrds [6]

I would feel warm because putting cold and hot together is gonna be warm because with the cold it is cooling down the hot to make warm

5 0

3 years ago

Ml(d^2θ/dt^2) =-mgθ

Nata [24]

The equation of motion of a pendulum is:

$\dfrac{\textrm{d}^2\theta}{\textrm{d}t^2} = -\dfrac{g}{\ell}\sin\theta,$

where $\ell$ it its length and $g$ is the gravitational acceleration. Notice that the mass is absent from the equation! This is quite hard to solve, but for small angles ( $\theta \ll 1$ ), we can use:

$\sin\theta \simeq \theta.$

Additionally, let us define:

$\omega^2\equiv\dfrac{g}{\ell}.$

We can now write:

$\dfrac{\textrm{d}^2\theta}{\textrm{d}t^2} = -\omega^2\theta.$

The solution to this differential equation is:

$\theta(t) = A\sin(\omega t + \phi),$

where $A$ and $\phi$ are constants to be determined using the initial conditions. Notice that they will not have any influence on the period, since it is given simply by:

$T = \dfrac{2\pi}{\omega} = 2\pi\sqrt{\dfrac{g}{\ell}}.$

This justifies that the period depends only on the pendulum's length.

4 0

3 years ago