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3 years ago

Express 79 m in units of (a) centimeters

Physics

1 answer:

dem82 [27]3 years ago

8 0

Answer: a) 7,00 centimeters

(b) 259. 19 feet

(d) 0.049 miles

Explanation:

(a) We know that 1 meter = 100 centimeters

Therefore,

$79\ m= 7,900\text{ centimeters}$

(b)Since 1 meter = 3.28084 feet

Then, $79\ m= 79\times3.28084=259.18636\approx 259.19\text{ feet}$

(c) Since, 1 feet = 12 inches.

$79\ m=259.19\text{ feet}=259.19\times12=3110.28\text{ inches}$

(d) $\text{Since 1 feet= }\dfrac{1}{5280}\text{ mile}$

$79\ m=259.19\text{ feet}=\dfrac{259.19}{5280}= 0.0490890151515\approx0.049\text{ miles}$

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Please help! the mass of an object is measured on a pan balance with a precision of 0.005 g and the recorded value of 128.01 g.

inysia [295]

Yes, these two objects have different masses.

<h3>How can we calculate that this statement is right ?</h3>

To calculate the precision of mass we are using the formula,

Precision(P) = $\frac{m_1}{m_1+\triangle m}$

Or, $\triangle$ m= $\frac{m_1}{P}$ -m₁

For the first case we are given,

m₁= The recorded value of mass

= 128.01 g

P= Precision of the mass

=0.005g

So, according to the formula, $\triangle$ m will be,

$\triangle$ m= $\frac{128.01}{0.005}$ -128.01

Or, $\triangle$ m=25,473.99 g

Or, $\triangle$ m=25.47 Kg

For the first case $\triangle$ m is 25.47 Kg..

For the second case we are given,

m₁= The recorded value of mass

= 0.13 Kg

P= Precision of the mass

=0.005 Kg

So, according to the formula, $\triangle$ m will be,

$\triangle$ m= $\frac{0.13}{0.005}$ -0.13

Or, $\triangle$ m= 25.87 kg

For the second case $\triangle$ m is 25.87 Kg.

For the two cases $\triangle$ m has different values, 25.47 Kg≠25.87 Kg.

Therefore we can conclude that, these two objects have different masses.

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1 year ago

Variations in the reactive properties of different organic molecules are most closely associated with _____.

azamat

Answer:

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Explanation:

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In organic chemistry, the functional group is a set of submolecular structures, characterized by a specific elementary connectivity and composition that confers specific chemical reactivity to the molecule that contains them. These structures replace the hydrogen atoms lost by saturated hydrocarbon chains. Aliphatic, or open chain, groups are usually represented generically by R (alkyl radicals), while aromatic ones, or derivatives of benzene, are represented by Ar (aryl radicals).

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