From 8:25 am to 30 seconds past 8:29 am, there are 4.5 minutes. Her speed is calculated by dividing the distance of the post office from her house by the time.
Speed = 0.75 mile / 4.5 minutes = 1/6 mile / minute
Determining the number of minutes she will have to take in order to reach school,
Time = 3.42 mile / (1/6 mile/minute) = 20.52 minutes
Adding this to the initial time,
Final time = 8:25 am + 20.52 minutes
= 8:45 am and 31.2 seconds.
She will reach the school on time even without increasing her speed.
Following changes are made in graph of G(x) to obtain F(x)
1) Vertical stretch by a factor of 2
So, G(x) will be changed to 2G(x)
2) Shift towards Right by 2 units
So, 2G(x) will be changed to 2G(x - 2)
3) Upward shift by 2 units.
So, 2G(x - 2) will be changed to 2G(x - 2) + 2
Thus,
F(x) = 2G(x - 2) + 2
F(x) = 2(x - 2)² + 2
Therefore, option C is the correct answer
Answer:
y= 7 and -1
Step-by-step explanation:
