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dlinn [17]
3 years ago
14

Type the correct answer in each box. Spell all words correctly, and use numerals instead of words for numbers. If necessary, use

/ for the fraction bar(s).
A café owner is designing a new menu and wants to include a decorative border around the outside of her food listings. Due to the cost of printing, the border should have an area of 48 square inches. The width of the border needs to be uniform around the entire menu. She has already determined that her food listings will fit within a 13-inch by 9-inch rectangular area.



The area of the decorative border can be modeled by the following equation, where x represents the width of the decorative border.

___x2 + ____ x = ____

Is it reasonable for the border to be 2.5 inches wide? ______(yes/no)
Mathematics
2 answers:
TEA [102]3 years ago
6 0

Answer:

  • 4x^2 +44x = 48
  • No, it is not reasonable

Step-by-step explanation:

If x is the width of the border, it adds 2x to each food listing dimension. The overall area of the menu and border will be ...

  total area = (13+2x)(9+2x) = 4x^2 +44x +117

The area of the food listing is ...

  food listing area = (13)(9) = 117 . . . . square inches

So, the border area is the difference of these:

  border area = total area - food listing area

  border area = (4x^2 +44x +117) - (117)

  border area = 4x^2 +44x

We want this to be 48 square inches, so a suitable model is ...

  4x^2 +44x = 48

__

It is not reasonable for the border to be 2.5 inches wide.

_____

<em>Why 2.5 inches is not reasonable</em>

Dividing by 4 the equation becomes ...

  x(x +11) = 12

One of the solutions is x=1. Using the value 2.5 for x would give ...

  2.5(13.5) = 12 . . . . . false

Bumek [7]3 years ago
4 0

Answer:

\displaystyle 4x^2 + 44 = 48

Step-by-step explanation:

\displaystyle [2x + 9][2x + 13] + 117 = 165 \\ \\ 4x^2 + 44x + 117 = 165 \\ \\ 4x^2 + 44x - 48 \\ [4x^2 + 48x] - [4x - 48] \\ 4x[x + 12] \: - 4[x + 12] \\ \\ [4x - 4][x + 12] \\ \\ -12, 1 = x

Since we are talking about LENGTHS, we only want the NON-NEGATIVE root, which in this case is 1, therefore the border is one inch wide, so 2½ inches is NOT reasonable.

I am joyous to assist you anytime.

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3 0
3 years ago
If f(2) = 13 and f '(x) ≥ 3 for 2 ≤ x ≤ 4, how small can f(4) possibly be?
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8 0
3 years ago
What is the domain of the function y = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="
tatiyna

Answer:

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4 0
3 years ago
Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body
nika2105 [10]

Answer:

The  position at time t  is  s(t) = 8t^2 -  14t   -8

Step-by-step explanation:

From the question we are told that

   The acceleration is  a =  16

   The velocity at t = 0  is  v(0) =  -14

    The  position at time t =  0  is s(0) =  -8

Generally acceleration is mathematically represented as

     a(t) =  \frac{d v}{dt }

=>   \frac{dv}{dt}  =  16

=>   dv  =  16 dt

integrating both sides we have    

     \int\limits dv  =  \int\limits16 dt

=>  v(t)  =  16 t  + c

Now at t = 0  

     v(0) =  16 * 0 +c  =  -14

=>  c =  -14

So

   v(t)  =  16 t  -14

Generally the position of the body is mathematically represented as

     s(t) =  \int\limits v(t)dt

So

    s(t) =  \int\limits 16t -  14  dt

So  

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Now  at t =  0

     s(0) = 16 \frac{0^2}{2} -  14(0)  + C =  -8

=>    C =  -8

So

   s(t) = 8t^2 -  14t   -8

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Paha777 [63]
The answer is its in the ones place
5 0
3 years ago
Read 2 more answers
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